Yet another way of doing it:
> x <- c(2,3)
> x + rep(seq(0, by=3, length=4), each=length(x))
[1] 2 3 5 6 8 9 11 12
On Fri, May 22, 2009 at 11:01 AM, Rowe, Brian Lee Yung (Portfolio Analytics)
<b_r...@ml.com> wrote:
> So if I want to concatenate the output of multiple seq calls, there's no
> clear way to to do this?
>
> For background, I have a number of data.frames with the same structure in a
> list. I want to 'collapse' the list into a single data.frame but only
> keeping certain columns from each underlying data.frame. In my example
> below, I want to keep columns 2,3 in each underlying data.frame.
>
> I'm using do.call('cbind', my.list) and then using the statement below to
> extract only the columns I need (other details omitted for brevity). If
> there's a built-in or pre-built function to do this, I'm all eyes.
>
>
> Brian
>
> PS if this is unclear, flame away, and I'll post some code
>
> -----Original Message-----
> From: Peter Dalgaard [mailto:p.dalga...@biostat.ku.dk]
> Sent: Friday, May 22, 2009 6:20 AM
> To: Rowe, Brian Lee Yung (Portfolio Analytics)
> Cc: r-help@r-project.org
> Subject: Re: [R] Behavior of seq with vector from
>
>
> Rowe, Brian Lee Yung (Portfolio Analytics) wrote:
> ....
> > To get the value I want, I am using the following code:
> >> sort(as.vector(apply(array(c(2,3)), 1, seq, by=3,length.out=4)))
> > [1] 2 3 5 6 8 9 11 12
> >
> > So two questions:
> > 1. Is seq designed/intended to be used with a vector from argument, and
> > is this the desired behavior?
> > 2. If so, is there a cleaner way of implementing what I want?
>
> 1. Hmm, not really. NA.
>
> 2. I'd view it as an outer sum, stringed out to a single vector, hence:
>
> > c(outer(c(2,3), seq(0,,3,4), "+"))
> [1] 2 3 5 6 8 9 11 12
>
>
> --
> O__ ---- Peter Dalgaard Øster Farimagsgade 5, Entr.B
> c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
> (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918
> ~~~~~~~~~~ - (p.dalga...@biostat.ku.dk) FAX: (+45) 35327907
>
>
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