Daren, what are you trying to achieve? Why don't you want any negative numbers? Anyway, if you only need positive values, why not: set.seed(999) v<-rnorm(20,mean=2,sd=0.5) (v) (sd(v))
Dimitri On Wed, Apr 22, 2009 at 1:26 AM, Daren Tan <darenta...@gmail.com> wrote: >> set.seed(999) >> abs(rnorm(20)) > [1] 0.28174016 1.31255963 0.79518398 0.27007049 0.27730642 0.56602374 > 1.87865826 1.26679114 0.96774968 1.12100936 1.32546371 0.13397739 > 0.93874945 > [14] 0.17253810 0.95765045 1.36268625 0.06833513 0.10065765 0.90134475 > 2.07435711 >> v <- abs(rnorm(20)) >> v > [1] 1.2285633 0.6430443 0.3597629 0.2940356 1.1252685 0.6422657 > 1.1067376 0.8848404 1.5540951 0.1266790 2.3826642 0.6012761 0.1793613 > 1.0805315 0.2468121 > [16] 2.1137370 0.3705275 0.5228678 0.5178055 1.4025109 > > How do I select numbers from v such that the standard deviation of the > new vector is less than 0.5 ? > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Dimitri Liakhovitski MarketTools, Inc. dimitri.liakhovit...@markettools.com ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
