one way is:
list1 <- as.data.frame(list(open=c(1,5), close=c(2,10)))
list2 <- as.data.frame(list(open=c(1.5,3), close=c(2.5,10)))
data.frame(
open = pmax(list1$open, list2$open),
close = pmin(list1$close, list2$close)
)
I hope it helps.
Best,
Dimitris
Thomas Meyer wrote:
Hi,
Algorithm question: I have two sets of "intervals", where an interval is
an ordered pair [a,b] of two numbers. Is there an efficient way in R to
generate the intersection of two lists of same?
For concreteness: I'm representing a set of intervals with a data.frame:
> list1 = as.data.frame(list(open=c(1,5), close=c(2,10)))
> list1
open close
1 1 2
2 5 10
> list2 = as.data.frame(list(open=c(1.5,3), close=c(2.5,10)))
> list2
open close
1 1.5 2.5
2 3.0 10.0
How do I get the intersection which would be something like:
open close
1 1.5 2.0
2 5.0 10.0
I wonder if there's some ready-built functionality that might help me
out. I'm new to R and am still learning to vectorize my code and my
thinking. Or maybe there's a package for interval arithmetic that I can
just pull off the shelf.
Thanks,
-tom
--
Dimitris Rizopoulos
Assistant Professor
Department of Biostatistics
Erasmus University Medical Center
Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands
Tel: +31/(0)10/7043478
Fax: +31/(0)10/7043014
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