So what about
threshold <- 0.5
plot(NA, xlab="", ylab="", main="", axes=F, xlim=c(0,1),
ylim=c(0,1), xaxs="i", yaxs="i")
legend1 <- substitute("Up (" * phantom() >= threshold * ")",
list(threshold=threshold))
legend(x=0, y=1, fill=c("orange", "white", "green", "gray90"),
cex=0.8, pt.cex=1.8, x.intersp=0.6, bg = "white", bty = "n",
legend =
do.call("expression", list(legend1, "Normal", "Down", "NA")))
Daren Tan wrote:
I tried sprintf and paste, which solves one of my problem i.e.
replacing the variable name by its value. However, >= is not renderend
correctly as the inequality symbol.
On Tue, Mar 24, 2009 at 12:24 PM, Gabor Grothendieck
<ggrothendi...@gmail.com> wrote:
For the legend argument try this:
leg = as.expression(c(sprintf("Up (>= %d)", threshold),
"Normal", "Down", "NA"))
or use paste in place of sprintf.
On Mon, Mar 23, 2009 at 11:53 PM, Daren Tan <darenta...@gmail.com> wrote:
I need to have the maths symbol for >= in the legend, and to
substitute threshold variable with its value. Somehow, various
attempts weren't successful. Please help.
threshold <- 0.5
plot(NA, xlab="", ylab="", main="", axes=F, xlim=c(0,1), ylim=c(0,1),
xaxs="i", yaxs="i")
legend(x=0, y=1, fill=c("orange", "white", "green", "gray90"),
cex=0.8, pt.cex=1.8, x.intersp=0.6, bg = "white",
legend=c(expression("Up (" >= threshold ")"), "Normal",
"Down", "NA"), bty = "n")
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
