Thanks. That worked. On Mon, Mar 23, 2009 at 2:17 PM, Phil Spector <spec...@stat.berkeley.edu>wrote:
> Suppose your matrix is called "x". Then > > x[,seq(1,ncol(x),n)] > > will give you what you want. > > - Phil Spector > Statistical Computing Facility > Department of Statistics > UC Berkeley > spec...@stat.berkeley.edu > > > > On Mon, 23 Mar 2009, akintayo holder wrote: > > Hi, >> I have a matrix and I want to create a matrix that includes every nth >> column >> of the original matrix. Does anyone know how I can go about doing that ? >> Or >> if you have an idea how I can do the same thing with a data frame ? If you >> can just point me towards the appropriate function I would appreciate it. >> Thanks >> >> [[alternative HTML version deleted]] >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> >> [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
