> That's what I meant by element-by -element. A vector in R corresponds
> to a row or a column in Excel, and a vector operation in R corresponds
> to a row or column of formulae, e.g.
>
> Excel
> A B C
> 1) 5 10 a1+b1 (= 15)
> 2) 3 2 a2+b2 (= 5)
> etc.
>
> R
> A <- c(5,3)
> B <- c(10,2)
> C <- A + B
Steve, I still don't understand the analogy. I agree that in this case the R
approach is vectorized. However, your function just as you first proposed it
will not work without a loop.
> max and pmax are equivalent in this case. I just use pmax as my
> default because it acts like other arithmetic operators (+, *, etc.)
> which perform pointwise (element-by-element) operations.
It's true. I changed it because I had applied your original version of mr()
to the entire vector x, which gave an incorrect result (perhaps "range" was
recycled in "idx <- which(x<=range)[1]"). If I used max instead of pmax, and
ever happened to use mr() without a loop, the length of the result would be
strange enough for me to realise the error. But then again, I added the "if
(length(x) >1) stop("x must have length 1")" line, so using max or pmax now
doesn't really make a difference, apart perhaps from run time.
> Using cut/split seems like gross overkill here. Among other things,
> you don't need to generate labels for all the different ranges.
>
> which(x<=range)[1]
> seems straightforward enough to me,
I could edit the mr_2() function a little bit to make it more efficient. I
left it mostly unchanged for the thread to be easier to follow. For example
I could replace the last four lines for only:
product <- x*percent
ifelse(product< minimum, minimum, product)
But I believe you refer to the cut/split functions rather. I agree that
"which(x<=range)[1]" is straighforward, but using such expression will
require a loop to pull the trick, which I don't intend. Am I missing
something?
Regards,
Diego
Stavros Macrakis-2 wrote:
>
> Using cut/split seems like gross overkill here. Among other things,
> you don't need to generate labels for all the different ranges.
>
> which(x<=range)[1]
>
> seems straightforward enough to me, but you could also use the
> built-in function findInterval.
>
> -s
>
> ______________________________________________
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> PLEASE do read the posting guide
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> and provide commented, minimal, self-contained, reproducible code.
>
>
-----
~~~~~~~~~~~~~~~~~~~~~~~~~~
Diego Mazzeo
Actuarial Science Student
Facultad de Ciencias Económicas
Universidad de Buenos Aires
Buenos Aires, Argentina
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