You are mostly correct. Because of the censoring issue, there is no good estimate of the mean survival time. The survival curve either does not go to zero, or gets very noisy near the right hand tail (large standard error); a smooth parametric estimate is what is really needed to deal with this. For this reason the mean survival, though computed (but see the survfit.print.mean option, help(print.survfit)) is not highly regarded. It is not an option in predict.coxph. Terry T. ----begin included message -------------- Hi,
if I got it right then the survival-time we expect for a subject is the integral over the specific survival-function of the subject from 0 to t_max. If I have a trained cox-model and want to make a prediction of the survival-time for a new subject I could use survfit(coxmodel, newdata=newSubject) to estimate a new survival-function which I have to integrate thereafter. Actually I thought predict(coxmodel, newSubject) would do this for me, but I?m confused which type I have to declare. If I understand the little pieces of documentation right then none of the available types is exactly the predicted survival-time. I think I have to use the mean survival-time of the baseline-function times exp(the result of type linear predictor). Am I right? ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.