How about this: > dat<-c(0.00377467,0.00377467,0.00377467,0.00380083,0.00380083,0.00380083,0.00380959, + 0.00380959,0.00380959,0.00380083,0.00380083,0.00380083) > dat[seq(1, by=3, to=length(dat))] <- 0 > dat [1] 0.00000000 0.00377467 0.00377467 0.00000000 0.00380083 0.00380083 0.00000000 0.00380959 0.00380959 0.00000000 0.00380083 [12] 0.00380083 >
On Thu, Feb 19, 2009 at 1:47 AM, Gundala Viswanath <gunda...@gmail.com> wrote: > Hi, > > I have a vector that look like this: > >> dat > V1 V2 V3 V4 V5 V6 > 0.00377467 0.00377467 0.00377467 0.00380083 0.00380083 0.00380083 > V7 V8 V9 V10 V11 V12 > 0.00380959 0.00380959 0.00380959 0.00380083 0.00380083 0.00380083 > > > what I want to do is to insert 0 (zero) for every 3 position yielding: > > V1 V2 V3 V4 V5 V6 > V7 V8 > 0 0.00377467 0.00377467 0.00377467 0 0.00380083 0.00380083 0.00380083 > V9 V10 V11 V12 V13 V14 > V15 V16 > 0 0.00380959 0.00380959 0.00380959 0 .00380083 0.00380083 0.00380083 > > > Is there a quick way to do it in R? > > - Gundala Viswanath > Jakarta - Indonesia > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve? ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
