thank you very much for your reply.
i studied the code you gave me and tried to make adjustments to fit the
requirements that i need, thank you again.. i used the following codes:
> m <- read.table("D:/documents/5 stations/01014000.csv", sep =",")
> z <- zoo(m[,4],as.Date(as.character(DF[,3]), "%m/%d/%Y"))
> x <- aggregate(z, cut(time(z),"y"), max)
i got the maximum values right using coredata(), my question now is, how can
i call for the complete date (yyyy-mm-dd) and the year (yyyy) when the
maximum observation for that year was observed?
CJ Rubio wrote:
>
> hi everyone!
>
> hope you can help me here.
>
> i am a new R user. what i am trying to do is to find the maximum annual
> discharge from a daily record. i have a data.frame which includes date and
> the discharge. somewhat like this..
>
> 10/1/1989 2410
> 10/2/1989 2460
> 10/3/1989 2890
> ...
> ...
> ...
> 12/31/2005 5730
>
> i have been browsing through the archives and fount out about the
> aggregate function and the zoo package. here's one of the codes i've tried
>
> DF <- read.table(data[i], sep =",") ##i have several stations to
> assimilate
> Date <- as.Date(as.character(DF[,3]), "%m/%d/%Y") #the date is at the 3rd
> column, obviously
> library(zoo)
> z <- aggregate(zoo(DF[,4]), cut(Date, "y"), max)
> max.discharge <- coredata(z)
> date <- time(z)
>
> the result should somehow look like this
> 11/21/1926 32600
> 4/24/1927 66500
> ...
> ...
> ..
> 4/26/2005 111000
>
> thanks for your time reading my questions,, any suggestions will be truly
> appreciated...
>
>
>
>
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