If you are looking for a solution to a polynomial equation with imaginary solutions you could use polyroot(). Example: To solve the equation: 1 + x + x^3 + 2*x^4 = 0 you create a vector with the coefficients of x and use polyroot:
z <- matrix(c(1,1,0,1,2), ncol=1) polyroot(z) Also try ?polyroot Rafael Paul Smith wrote: > > On Sat, Feb 7, 2009 at 10:20 AM, oryie <43248...@qq.com> wrote: >> I want to use R to calculate the variable x which is in some eqation, >> give >> an example: >> >> 3*x-log(x)+1=0, >> >> how to solve equation to get the exact x in R? > > You could use uniroot(), but your equation has no real solution. > > Paul > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > -- View this message in context: http://www.nabble.com/R-solve-equation-tp21886831p21903933.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
