Hi Jörg, If I understood, apply(yourdataframe,2,function(x) x[diff(which(x==1 | x==3))])
should do what you want. HTH, Jorge On Sun, Jan 25, 2009 at 5:53 PM, Jörg Groß <jo...@licht-malerei.de> wrote: > is there a way to do that without generating a data.frame? > > In my real data, I have a big data.frame and I have to compare over > different columns... > > > Am 25.01.2009 um 23:42 schrieb Gabor Grothendieck: > > > Try this: >> >> DF <- data.frame(x, nxt = c(tail(x, -1), NA), prv = c(NA, head(x, -1))) >>> DF >>> >> x nxt prv >> 1 1 2 NA >> 2 2 3 1 >> 3 3 4 2 >> 4 4 5 3 >> 5 5 2 4 >> 6 2 6 5 >> 7 6 NA 2 >> >>> subset(DF, nxt == 3 & prv == 1)$x >>> >> [1] 2 >> >> >> On Sun, Jan 25, 2009 at 5:29 PM, Jörg Groß <jo...@licht-malerei.de> >> wrote: >> >>> Hi, >>> >>> I have a quit abstract problem, hope someone can help me here. >>> >>> I have a vector like this: >>> >>> >>> x <- c(1,2,3,4,5,2,6) >>> x >>> >>> [1] 1 2 3 4 5 2 6 >>> >>> now I want to get the number where the previous number is 1 and the next >>> number is 3 >>> (that is the 2 at the second place) >>> >>> I tried something with tail(x, -1) ... >>> with that, I can check the next number, but how can I check the previous >>> number? >>> >>> ______________________________________________ >>> R-help@r-project.org mailing list >>> https://stat.ethz.ch/mailman/listinfo/r-help >>> PLEASE do read the posting guide >>> http://www.R-project.org/posting-guide.html >>> and provide commented, minimal, self-contained, reproducible code. >>> >>> > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]]
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