Dear all,
I've got a list
L <- list(L1 = list
(foo = "bar"
, SL = NULL
)
, L2 = list
(
foo = "bar"
, SL = list
(SSL1 = list
(DF = data.frame(val = 21, foo = "bar")
, DFOO = list(foo = "foo", bar = "bar")
)
, SSL2 = list
(DF = data.frame(val = 22, foo = "bar")
, DFOO = list(foo = "foo", bar = "bar")
)
)
)
, L3 = list
(
foo = "bar"
, SL = list
(SSL1 = list
(DF = data.frame(val=31, foo="bar")
, DFOO = list(foo="foo", bar="bar")
)
)
)
)
from which I'ld like to extract the values 21,22 and 31.
lapply(
lapply(
lapply(
lapply(L, "[[","SL")
,"[[",1)
,"[[","DF")
,"[[","val")
gives me 21 and 31. Because of lapply(...,"[[",1), it searches through
the first element of each SL, which are the SSL1. It misses SSL2. Is
there a way to replace the ,"[[",1), with a regex or the like to get the
job done? Does anybody now any other solution?
Thanks and regards,
Dominik
----------------------------------------------
Andreas Dominik Cullmann
Forstliche Versuchs- und Forschungsanstalt
Wonnhalde 4
79100 Freiburg
Tel. +49 761 4018 204
Email: dominik.cullm...@forst.bwl.de
<mailto:dominik.cullm...@forst.bwl.de>
Homepage: www.fva-bw.de <http://www.fva-bw.de>
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