On 11/19/2008 11:27 AM, Brigid Mooney wrote:
Hi All,
I'm sorry I haven't been able to find anything that will help me with this
problem, and I'm still pretty new to R - so any help here is greatly
appreciated!
I am looking to create a vector in a sequential process where each entry in
the vector is a data frame, for example:
days <- 3
for (i in 1:days)
{
FOO[i] <- data.frame(x=c(i, i+1, i+2), y=c(i, i*i, i*i*i))
}
but when I try this, I get the error "object "FOO" not found".
I tried to avoid this by concatenating blank data frames to create a shell
for FOO via:
FOO <- rep(data.frame(), times=days)
You want to create FOO as a "list", which is the generic vector type in
R. That is:
FOO <- list()
days <- 3
for (i in 1:days)
{
FOO[[i]] <- data.frame(x=c(i, i+1, i+2), y=c(i, i*i, i*i*i))
}
Note the use of [[]] indexing on FOO: FOO[i] would be a list shortened
to just one element; FOO[[i]] is that element. (This distinction only
matters when working with types like lists. There's no such thing as a
numeric value that's not in a numeric vector, so x[[2]] and x[2] are the
same thing if x is numeric.)
Duncan Murdoch
before the other lines, but then I get lots of errors relating to replacing
0 rows with 3 rows.
Needless to say, the data frames I am actually dealing with are quite a bit
larger than listed here - so I wanted to get the process working on a toy
example first.
Thanks in advance for your help!
for (i in 1:3)
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and provide commented, minimal, self-contained, reproducible code.
