On Oct 16, 2008, at 12:55 PM, Jorge Ivan Velez wrote:
Dear Jörg,
See ?cut and ?table. Is this what you want?
x <- c(1, 3, 1.2, 5, 5.9)
table(cut(x,breaks=c(0,2,4,6)))
(0,2] (2,4] (4,6]
2 1 2
Perhaps even greater future efficiency could be had by also adding
?seq
table(cut(x, breaks=seq(0, 6, by=2)))
A couple more keysrokes in this toy example but scales up much better
to the requested purpose of evenly divided interval.
The OP should also note carefully the open aspect on the left of these
intervals. That can be controlled with option in cut:
> x <- c(1, 3, 1.2, 5, 5.9, 6)
> table(cut(x, breaks=seq(0,6,by=2)))
(0,2] (2,4] (4,6]
2 1 3
> x <- c(1, 3, 1.2, 4, 5, 5.9, 6)
> table(cut(x, breaks=seq(0,6,by=2)))
(0,2] (2,4] (4,6]
2 2 3
> table(cut(x, breaks=seq(0,6,by=2), right=FALSE))
[0,2) [2,4) [4,6)
2 1 3
--
David Winsemius
Heritage Labs
HTH,
Jorge
On Thu, Oct 16, 2008 at 12:46 PM, Jörg Groß <[EMAIL PROTECTED]>
wrote:
Hi,
Is there a function which counts the frequencies of the occurence
of a
number within an interval?
for example I have this vector:
x <- c(1, 3, 1.2, 5, 5.9)
and I want a vector that gives me the frequencies within an
interval of 2,
beginning at 0
(so the intervals are 0-2, 2-4, 4-6 and so on)
so I get these frequencies:
2, 1, 2
Which functions do I have to use for this purpose?
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and provide commented, minimal, self-contained, reproducible code.
______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
