Hi, i am doing a statistics course and am having trouble with an exercise where i need to determine whether my success rate at something is higher than 80%. I was successful in 29 out of 60 trials, so these were the commands i entered into R: >n=60 >p.hat=29/n >p.0=0.8 >se.0=sqrt(p.0*(1-p.0)/n) >z=(p.hat-p.0)/se.0 >print(z) Which returned: [1] -6.132224 >1-pnorm(z) Which returned [1] 1
My problem is that i am meant to state a null and alternative hypothesis which at the moment i have stated as p>0.8 (null) and p≤0.8 (alternative). As things stand, though, a p-value of 1 suggests i should reject the null hypothesis which can't be right since i am obviously successful less than 80% of the time. I am not sure where i am getting muddled. Any advice would be greatly appreciated. Thanks! -- View this message in context: http://www.nabble.com/One-sample-test-for-p-tp20010677p20010677.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
