Sorry about the html-formatted message. Here it is again in plain text. Hello,
The function qt returns NaN for degrees of freedom <1. For example: > qt(0.5,0.5) [1] NaN Warning message: In qt(p, df, lower.tail, log.p) : NaNs produced But qt(0.5,0.5) should be 0, since the distribution is symmetric. > pt(0,0.5) [1] 0.5 It actually fails with any value, as long as df<1. Is this a bug, or is there some fundamental reason why this cannot be computed? Thank you, Enrico ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
