Try

library(fortunes); fortune("Type III")

(Try it multiple times as there are two relevant quotes: one is to
http://www.stats.ox.ac.uk/pub/MASS3/Exegeses.pdf)

I would not expect modern statistics courses to discuss this issue (or even ANOVA except for historical information), as with an interactive computing system you can test any two nested models (and not just linear Gaussian models). It relates to the mindset of batch-mode packages like SAS of the 1960s, and seemed old-fashioned even when I first taught the area in 1979 (using GLIM).

For Bill Venables' preferred approach see Chapter 6 of MASS (the book, any edition).



On Fri, 26 Sep 2008, Stefan Uhmann wrote:

Dear list,

slightly OT: can you recommend me any sources where I can find more about this Type I - II - III anova problem? It seems as my statistics courses did not cover this issue, so I feel rather naive and have this sort of feeling that some of my analyses might be complete nonsense.

Regards,
Stefan

John Fox schrieb, Am 26.09.2008 12:36:
Dear Menelaos,

-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On
Behalf Of Menelaos Stavrinides
Sent: September-25-08 9:56 PM
To: r-help@r-project.org
Subject: [R] Type I and Type III SS in anova

Hi all,
I have been trying to calculate Type III SS in R for an unbalanced two-way
anova. However, the Type III SS are lower for the first factor compared to
type I but higher for the second factor (see below). I have the impression
that Type III are always lower than Type I - is that right?

No.

And a clarification about how to fit Type III SS. Fitting
model<-aov(y~a*b)
in the base package and then loading car / changing contrasts / running
Anova(model,type=c("III")) gives different results compared to loading car
/
changing contrasts / fitting model<-aov(y~a*b) / running
Anova(model,type=c("III")). However summary(model) gives the same results
in
both cases. Is this how it is set up?

If you use "type-III" tests in an unbalanced ANOVA, and want to test
sensible hypotheses, you should use an orthogonal row-basis for the effects,
such as is provided by contr.helmert, contr.poly, or contr.sum, but not by
the default contr.treatment. When you fit a model before changing the
contrast type, contr.treatment is used. Changing the contrast type
subsequent to that has no effect on a model that's already fit (how could
it, unless, e.g., the model is updated?). Because the summary method for aov objects reports "typei-I" (sequential) tests, the results are independent of
the contrast type.

Regards,
 John

local({pkg <- select.list(sort(.packages(all.available = TRUE)))
+ if(nchar(pkg)) library(pkg, character.only=TRUE)})
options(contrasts=c("contr.helmert","contr.poly"))
model2<-aov(tdrate~temp*sex)
summary(model2)
             Df   Sum Sq  Mean Sq   F value  Pr(>F)
temp          3 0.110137 0.036712 1005.6947 < 2e-16 ***
sex           1 0.000141 0.000141    3.8593 0.05095 .
temp:sex      3 0.000154 0.000051    1.4073 0.24206
Residuals   187 0.006826 0.000037
---
Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
Anova(model2,type=c"III")
Error: unexpected string constant in "Anova(model2,type=c"III""
Anova(model2,type=c("III"))
Anova Table (Type III tests)

Response: tdrate
             Sum Sq  Df    F value  Pr(>F)
(Intercept) 0.57549   1 15764.9249 < 2e-16 ***
temp        0.08571   3   782.6314 < 2e-16 ***
sex         0.00023   1     6.2851 0.01303 *
temp:sex    0.00015   3     1.4073 0.24206
Residuals   0.00683 187
---
Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1

--
Menelaos Stavrinides
Ph.D. Candidate
Environmental Science, Policy and Management
137 Mulford Hall MC #3114
University of California
Berkeley, CA 94720-3114 USA
Tel: 510 717 5249

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--
Brian D. Ripley,                  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford,             Tel:  +44 1865 272861 (self)
1 South Parks Road,                     +44 1865 272866 (PA)
Oxford OX1 3TG, UK                Fax:  +44 1865 272595

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