On Thu, 25 Sep 2008, Mark Na wrote:
Hello,
I have a dataframe with 9 columns, and I would like to sort (order) the
right-most eight of them alphabetiaclly, i.e.:
ID1 ID2 F G A B C E D
would become
ID1 ID2 A B C D E F G
Right now, I'm using this code:
attach(data)
data<-data.frame(ID1,ID2,data[,sort(colnames(data)[3:9])])
detach(data)
but that's not very elegant. Ideally I could specify which columns to sort
and which to leave "as is" (but my attempts to do so have failed).
Thank you,
Mark
How about:
df <- data.frame(z=1:2,a=3:4,y=5:6)
df
z a y
1 1 3 5
2 2 4 6
sortdf <- df[,sort(names(df))]
sortdf
a y z
1 3 5 1
2 4 6 2
David Scott
_________________________________________________________________
David Scott Department of Statistics, Tamaki Campus
The University of Auckland, PB 92019
Auckland 1142, NEW ZEALAND
Phone: +64 9 373 7599 ext 86830 Fax: +64 9 373 7000
Email: [EMAIL PROTECTED]
Graduate Officer, Department of Statistics
Director of Consulting, Department of Statistics
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