Johannes Hüsing wrote:

Am 23.09.2008 um 23:57 schrieb Peter Dalgaard:

For this kind of problem I'd go directly for the binomial distribution. If the actual probability is 0, this is essentially deterministic and you can look at

> binom.test(0,99,p=.03, alt="less")


This means that you don't sample from the p=.03 population?
Note that there is a 5 per cent chance to have 0 failures in 99
trials with p=.03.
Yes, that's what I read the task as saying: Sample from p=0.00 when the hypothesis is p=0.03. Then rejection happens with probability 1 when n >= 99. Actually, he said that we could assume the _sample_ rate to be 0%, but that is only assured when p=0.0.

(You can continue the game by looking at the probability of getting 0 failures, depending on the true p. E.g., if p=0.001, we have

> dbinom(0, 99, 0.001)
[1] 0.9056978

i.e. 90% power to detect at 5% level. And further continue into a full power analysis where you calculate the probability of a failure rate that is significantly different from 0.03 depending on p and n.)

--
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 c/ /'_ --- Dept. of Biostatistics     PO Box 2099, 1014 Cph. K
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