Hmm, maybe it only works in my development version (to be released v. v. soon)
Hadley
On Mon, Sep 22, 2008 at 8:02 PM, Steven McKinney <[EMAIL PROTECTED]> wrote:
> Is something missing in the melt()?
>
>> x<-data.frame(x1=c(1,7),x2=c(4,6),x3=c(8,2))
>> require("reshape")
> Loading required package: reshape
>> dfm <- melt(x, id = c())
> Error in if (!missing(id.var) && !(id.var %in% varnames)) { :
> missing value where TRUE/FALSE needed
>> dfm[order(dfm$value), ]
> Error: object "dfm" not found
>> x
> x1 x2 x3
> 1 1 4 8
> 2 7 6 2
>> melt(x, id = c())
> Error in if (!missing(id.var) && !(id.var %in% varnames)) { :
> missing value where TRUE/FALSE needed
>>
>
>
> Steve McKinney
>
>
> -----Original Message-----
> From: [EMAIL PROTECTED] on behalf of hadley wickham
> Sent: Mon 9/22/2008 5:47 PM
> To: zhihuali
> Cc: [EMAIL PROTECTED]
> Subject: Re: [R] sort a data matrix by all the values and keep the names
>
> On Mon, Sep 22, 2008 at 6:54 PM, zhihuali <[EMAIL PROTECTED]> wrote:
>>
>> Dear all,
>>
>> If I have a data frame x<-data.frame(x1=c(1,7),x2=c(4,6),x3=c(8,2)):
>> x1 x2 x3
>> 1 4 8
>> 7 6 2
>>
>> I want to sort the whole data and get this:
>> x1 1
>> x3 2
>> x2 4
>> x2 6
>> x1 7
>> x3 8
>>
>> If I do sort(X), R reports:
>> Error in order(list(x1 = c(1, 7), x2 = c(4, 6), x3 = c(8, 2)), decreasing =
>> FALSE) :
>> unimplemented type 'list' in 'orderVector1'
>>
>> The only way I can sort all the data is by converting it to a matrix:
>>> sort(as.matrix(x))
>> [1] 1 2 4 6 7 8
>>
>> But now I lost all the names attributes.
>>
>> Is it possible to sort a data frame and keep all the names?
>
> Here's one way:
>
> dfm <- melt(x, id = c())
> dfm[order(dfm$value), ]
>
> Hadley
>
> --
> http://had.co.nz/
>
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--
http://had.co.nz/
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