Henrique Dallazuanna schrieb:
You can do this:
hh <- lapply(h, head, mh)
hh$breaks <- head(h$breaks, mh + 1)
class(hh) <- "histogram"
plot(hh)
Thanks a lot, that's exactly what I need :-) (I did not consider the class...)
Putting an xlim could also be an solution but I think this is much more clean
:-)
Ciao,
Antje
On Mon, Sep 1, 2008 at 10:44 AM, Antje <[EMAIL PROTECTED]
<mailto:[EMAIL PROTECTED]>> wrote:
Hi there,
I hope this question is not as stupid as the one before ...
I tried to shorten my histogram (because the distribution is quite
skewed and I simply don't want to see the long tail but still use
the histogram plot). How can I do something like this? (The example
does not work but I don't know why...)
data <- rnorm(100) # as example, of course this is not skewed...
h <- hist(data, plot=FALSE)
mh <- 5
hh <- list(h$breaks[0:(mh+1)],
h$counts[0:mh],h$intensities[0:mh],h$density[0:mh],h$mids[0:mh],h$xname,h$equidist)
names(hh) <- names(h)
plot(hh)
Antje
______________________________________________
R-help@r-project.org <mailto:R-help@r-project.org> mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
