When I try your suggestion, I get the output, e.g.,:
christina.df$gen: 309 NULL Returned for each vector. That doesn't seem good (I associate "NULL" with something being empty), but perhaps I am misinterpreting it? ----- Original Message ---- From: Dylan Beaudette <[EMAIL PROTECTED]> To: Josh B <[EMAIL PROTECTED]> Cc: r-help@r-project.org Sent: Wednesday, August 20, 2008 10:58:26 AM Subject: Re: [R] Looping over groups On Wed, Aug 20, 2008 at 7:48 AM, Josh B <[EMAIL PROTECTED]> wrote: > Hello, > > My R skills are somewhere between novice and intermediary, and I am hoping > that some of you very helpful forum members, whom I've seen work your magic > on other peoples' problems/questions, can help me here. > > I have a matrix with the following format: > > (i) individual plants comprising many different genotype groups (i.e., a > plant is genotype 1 or genotype 2 or genotype 3, etc). The column for > genotypes is called "gen", and the plants are members of genotype class 1 - > 309, with no overlaps (i.e., you're either a genotype 1 or a genotype > something else, but not both) and no missing values. > (ii) Various trait measurements taken on the plants, with multiple replicates > per genotype group > > I want to create a covariance matrix, separately for plants from each > genotype group. I know how to use the command "cov"; my problem is that I > have 309 different genotype groups and so I need to set up some sort of an > automated loop to go through each genotype group and create a separate > covariance matrix based on it. > > My question is, how do I make a loop to automatically go through and create > these covariance matrices, i.e., a separate covariance matrix for plants from > each genotype group? > > I am familiar with the "for" command, but I cannot get it to work. Here is my > code: > > christina= read.table("christina.txt", sep= ",", na= "NA", header= TRUE) > {for (i in 1:309) > christina.i= subset(christina, gen == i) > christina.i.clean= christina.i[,-1] > christina.matrix.i= as.matrix(christina.i.clean) > christina.cov.i= cov(christina.matrix.i, y= NULL, use= "complete.obs", > method= c("pearson")) > write.table(christina.cov.i, sep= ",", file= "covariances.csv", row.names= > FALSE, col.names= FALSE, append= TRUE)} > > > The problem occurs at my code snippet "gen == i". I want R to insert a number > in place of "i", depending on what round of the loop it is on, but R insists > that I am literally referring to a genotype class named "i". I have made sure > that the column "gen" is numeric, but the same problem persists if I make the > column a factor instead. > > Any help would be much appreciated, but help that includes sample code would > be most useful. Thank you in advance! > > Sincerely, > Josh > If you can make your data into a dataframe, you can use something like this: # might work christina.df <- as.data.frame(christina) # this should work, if your ID var ('gen') is the first column in the data frame by(christina.df, christina.df$gen, function(d) { d.clean <- d[,-1] cov(d.clean, y= NULL, use= "complete.obs", method= c("pearson") } ) for more ideas, see ?by Cheers, Dylan ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.