Try this: is.na(DF) <- is.na(DF)
or this which returns a transformed data frame without overwriting DF: replace(DF, is.na(DF), NA) On Fri, Aug 15, 2008 at 10:27 PM, Peck, Jon <[EMAIL PROTECTED]> wrote: > I am looking for the most efficient way to replace all occurrences of NaN in > a data frame with NA. I can do this with a double loop, but it seems that > there should be a higher level and more efficient way. With is.na, I could > use ifelse, but if.nan seems not to have similar capabilities. > > > > TIA, > > Jon Peck > > > > Jon K. Peck > > [EMAIL PROTECTED] > > > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
