Hi Kevin, check ?dump
set.seed(1234) list1 <- list(a1=rnorm(100), a2=rnorm(10)) list2 <- list(a1=rnorm(50), a2=rnorm(25)) mylist <- list(top1=list1, top2=list2) dump(list="mylist", file="mydumpedlist.r") rm(mylist) # please note that you have to quote the name # of the object(s) you want to dump! source("mydumpedlist.r") ls() I hope this helps, Roland [EMAIL PROTECTED] wrote:
I have a list List(Sku=" ", Shape=1, Scale=3, DayOfYear=daylist) Note: picture daylist as c(2,3,4,3) it is a list with variable length. Then I have a list of lists al <- c(al, List(List(Sku=" ", Shape=1, Scale=3, DayOfYear=daylist)) Note: same comment on daylist as above. So far this creates a list of lists just how I want it. If I do al[1] I get each member and the variable length list 'daylist'. Now I want to export this list of lists: write.table(mlist, "SkuInfo.dat", row.names = FALSE, sep=",") But I get an error that the list lengths are not equal. The only member of this list that has a variable length would be DayOfYear How can I output this list of lists when each element list contains a variable length list? Thank you. Kevin ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.