Kevin -

Read more closely "levels", being an optional vector of the values x might have taken. You are saying x might have taken 1:20, and then giving it the first 20 letters, which are not part of "the values x might have taken".

Try:

x <- factor(letters[1:20])
levels(x)
x

vs.

y <- factor(letters[1:20], levels = letters)
levels(y)
y

vs.

z <- factor(letters[1:20], levels = letters[1:19])
levels(z)
z

That might help show you what's going on?

Best,
Erik Iverson

[EMAIL PROTECTED] wrote:
Doing ?factor I get:

x a vector of data, usually taking a small number of distinct values. levels an optional vector of the values that x might have taken. The default is the set of values taken by x, sorted into increasing order.
So if I do:

factor(letters[1:20],level=seq(1:20)
 [1] <NA> <NA> <NA> <NA> <NA> <NA> <NA> <NA> <NA> <NA> <NA> <NA> <NA> <NA> <NA>
[16] <NA> <NA> <NA> <NA> <NA>
Levels: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

So why all of the NA? What happend to 'a'. 'b', etc.? I was expecting a=1, b=2, 
c=3 etc.

I am missing something. Please help with my understanding.
Keviin

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to