I am trying to do this using the copula library and find a possible way out.
library(copula) x=mvdc(claytonCopula(.75),c("exp","exp"),list(list(rate=1),list(rate=2))) x.sample=rmvdc(x,100) The above code gives a sample with two marginal exponential ditributions. But what does the first argument claytonCopula(.75) mean? How can one specify the correlation between these two marginals? Thanks Sincerely, Yanwei Zhang Department of Actuarial Research and Modeling Munich Re America Tel: 609-275-2176 Email: [EMAIL PROTECTED] -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Zhang Yanwei - Princeton-MRAm Sent: Wednesday, July 30, 2008 5:48 PM To: r-help@r-project.org Subject: [R] Sampling two exponentials Hi all, I am going to sample two variables from two exponential distributions, but I want to specify a covariance structure between these two variables. Is there any way to do it in R? Or is there a "Multivariate Exponential" thing corresponding to the multivariate normal? Thanks in advance. Sincerely, Yanwei Zhang Department of Actuarial Research and Modeling Munich Re America Tel: 609-275-2176 Email: [EMAIL PROTECTED]<mailto:[EMAIL PROTECTED]> [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.