Às 21:26 de 25/07/2025, ressw--- via R-help escreveu:
Make two objects
junk.A = -9999
junk.B = "junk.A"
rm(junk.B) removes junk.B and not junk.A, as it should.
Is there a function, e,g, "rm2", such that
rm2(junk.B) will delete junk.A and not junk.B?
Why doesn't this work?:
rm(eval(junk.B))
Error in rm(eval(junk.B)) : ... must contain names or character strings
since eval(junk.B) yields "junk.A"
and
rm("junk.A")
does work?
R version 4.3.0 (2023-04-21)
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide https://www.R-project.org/posting-
guide.html
and provide commented, minimal, self-contained, reproducible code.
Hello,
Just use rm's argument 'list'.
junk.A = -9999
junk.B = "junk.A"
rm(list = junk.B)
junk.A
#> Error: object 'junk.A' not found
junk.B
#> [1] "junk.A"
Hope this helps,
Rui Barradas
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide https://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.