try function na.locf() from package 'zoo', i.e., library(zoo) x <- c("A","B",NA,NA,"C",NA,NA,NA,NA,"D",NA,NA) na.locf(x)
I hope it helps. Best, Dimitris ---- Dimitris Rizopoulos Biostatistical Centre School of Public Health Catholic University of Leuven Address: Kapucijnenvoer 35, Leuven, Belgium Tel: +32/(0)16/336899 Fax: +32/(0)16/337015 Web: http://med.kuleuven.be/biostat/ http://perswww.kuleuven.be/dimitris_rizopoulos/ Quoting Owen Jones <[EMAIL PROTECTED]>:
I have a vector of data (species names) interspersed with NA values and I want a function to "fill in the blanks", replacing NA values with whatever the last species name was. For example the vector: "A","B",NA,NA,"C",NA,NA,NA,NA,"D",NA,NA. should evaluate to: "A" "B" "B" "B" "C" "C" "C" "C" "C" "D" "D" "D" I tried to use rle() in a function to do this but have hit a brick wall. How would YOU do this? Many thanks, Owen ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.