Hello,

I was working on an R script using the datediff object, to log certain 
durations in the data processing.
I ran in to the issue that outputing a datediff object using PASTE will leave 
out the time unit by default.

When you paste() or as.character() a datediff object it only outputs the 
numeric value, for example "1.23", so without the time unit secs, minutes, 
hours etc. This is arguably is not very useful, because 1.23 seconds is very 
different from 1.23 hours.

```
start_time <- Sys.time()
result <- sum(1:10000)
dur_time <- Sys.time() - start_time

print(paste(Sys.time(), "the process duration:", dur_time)) # "2024-10-23 
09:57:10.69578 the process duration: 0.00280904769897461"

print(dur_time)               # "Time difference of 0.002809048 secs"
print(paste(dur_time))        # "0.00280904769897461"
print(as.character(dur_time)) # "0.00280904769897461"
print(format(dur_time))       # "0.002809048 secs"

print(paste(dur_time, attr(dur_time, "units"))) # "0.00280904769897461 secs"
```

So my questions are:
1)  is it possible to have the default output for as.character for the datediff 
object also include the time unit? That way, it automatically outputs for 
example "1.23 seconds" when used in combination with paste().
If someone really need just the numeric value without the unit, you can already 
use as.numeric(dur_time).
2) Is it possible to expand the format() options for the datediff object, so 
that it also accepts a strptime-like string, so like %H:%M:%S ? That way you 
have more output options without having to rely on third-party libraries

regards,
Bas de reuver (UMCG, The Netherlands)
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