Re: [R] If loop

[Duncan Murdoch]

On 2024-08-09 6:21 a.m., Bert Gunter wrote:
"Or use <<- assignment I think.  (I usually return, but return can only
return one object and I think you want two or more"
You can return any number of objects by putting them in a list and
returning the list.
Use of "<<-" is rarely a good idea in R.

Proper use of "<<-" is often a good idea.  This wouldn't be what I'd 
call proper use.  The example in section 10.7 of the Intro manual is a 
good use.

It would be a positive change to the language if the target of the 
assignment was required to be an existing variable in a parent environment.

Duncan Murdoch



-- Bert

On Fri, Aug 9, 2024 at 1:53 AM CALUM POLWART <polc1...@gmail.com> wrote:

OK. The fact it's in a function is making things clearer.

Are you trying to update the values of an object from within the function,
and have them available outside the function. I don't speak functional
programming articulately enough but basically

v <- 1

funA <- function() {
v <- v+1
}

funA()
cat (v)

# 1

You either return the v from the function so

funB <- function() {
v <- v+1
return (v)
}

v <- funB()
cat (v)
#2

Or use <<- assignment I think.  (I usually return, but return can only
return one object and I think you want two or more

v <- 1
funC <- function() {
v <<- v+1
}

funC()
cat (v)
#2

On Fri, 9 Aug 2024, 09:03 Steven Yen, <st...@ntu.edu.tw> wrote:

Thanks. Hmm. The loop is doing what it is supposed to do.

try1<-function(joint12=FALSE,marg1=FALSE,marg2=FALSE,
+                cond12=FALSE,cond21=FALSE){
+ # ***************************************************
+ # Testing if loop
+ # ***************************************************
+ if(joint12){
+   {print ("joint12"); cat(joint12,"\n")}
+   {print ("marg1"); cat(marg1,"\n")}
+ } else if (marg1) {
+   {print ("marg1"); cat(marg1,"\n")}
+   {print ("joint12"); cat(joint12)}
+ } else if (marg2) {
+   {print ("marg2"); cat(marg2)}
+ } else if (cond12) {
+   {print ("cond12"); cat(cond12)}
+ } else {
+   {print ("cond21"); cat(cond21)}
+ }}
try1(joint12=TRUE)
[1] "joint12"
TRUE
[1] "marg1"
FALSE
try1(marg1=TRUE)
[1] "marg1"
TRUE
[1] "joint12"
FALSE
try1(marg2=TRUE)
[1] "marg2"
TRUE
try1(cond12=TRUE)
[1] "cond12"
TRUE
try1(cond21=TRUE)
[1] "cond21"
TRUE

On 8/9/2024 2:35 PM, CALUM POLWART wrote:

Is something wrong in the initialisation part that we don't see?

joint12 <- marg1 <-F

marg1 <-T

if (joint12) {
   print ("joint 12")
   cat (joint12)
}

if (marg1) {
   print("marg 1")
   cat(marg1)
}

Would probably be my diagnostic approach

On Fri, 9 Aug 2024, 04:45 Steven Yen, <st...@ntu.edu.tw> wrote:

Can someone help me with the if loop below? In the subroutine, I
initialize all of (joint12,marg1,marg2,cond12,cond21) as FALSE, and call
with only one of them being TRUE:

,...,joint12=FALSE,marg1=FALSE,marg2=FALSE,cond12=FALSE,cond21=FALSE,,,,

joint12 seems to always kick in, even though I call with, e.g., marg1
being TRUE and everything else being FALSE. My attempts with if... else
if were not useful. Please help. Thanks.

v1<-cprob(z1,x1,a,b,mu1,mu2,rho,j+1,k+1)
      v0<-cprob(z0,x0,a,b,mu1,mu2,rho,j+1,k+1)

     ...

      me1<-me0<-NULL
      if(joint12) {me1<-cbind(me1,v1$p12); me0<-cbind(me0,v0$p12)}
      if(marg1)   {me1<-cbind(me1,v1$p1); me0<-cbind(me0,v0$p1)}
      if(marg2)   {me1<-cbind(me1,v1$p2); me0<-cbind(me0,v0$p2)}
      if(cond12)  {me1<-cbind(me1,v1$pc12); me0<-cbind(me0,v0$pc12)}
      if(cond21)  {me1<-cbind(me1,v1$pc21); me0<-cbind(me0,v0$pc21)}
      ...

    labels<-NULL
    if(joint12) labels<-c(labels,lab.p12)
    if(marg1)   labels<-c(labels,lab.p1)
    if(marg2)   labels<-c(labels,lab.p2)
    if(cond12)  labels<-c(labels,lab.pc12)
    if(cond21)  labels<-c(labels,lab.pc21)

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______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.