I haven't tracked what went before, but your syntax here is totally messed
up:
for (i in seq_len(nrow(total_name)))
{
with(
total_name[i, ],
{
file.rename(total_name$orig, total_name$target)
}
)
}
Also, you don't need looping because file.rename is already vectorized --
you need to read the Help file more carefully. So something like this
should do what you want:
with(total_name, file.rename (orig, target))
where orig and target should be character (not factor) columns in your data
frame.
Cheers,
Bert
On Mon, Sep 19, 2022 at 10:38 AM Kai Yang via R-help <r-help@r-project.org>
wrote:
> Hi Rui,I put original file names and target file names into data frame:
> total_name. I can use
> file.rename("out_1.pdf", "abc_title.pdf")
>
> to rename a single file. But I hope to use loop to complete the task. So I
> write a code below:
> for (i in seq_len(nrow(total_name)))
> {
> with(
> total_name[i, ],
> {
> file.rename(total_name$orig, total_name$target)
> }
> )
> }
> But I got error message:
> Error in file.rename(total_name$orig, total_name$target) :
> invalid 'from' argument
>
> I think the problem happen due to quotation problem. Do you know how to
> fix it?
> Thanks,
> Kai On Friday, September 16, 2022 at 08:32:53 PM PDT, Rui Barradas <
> ruipbarra...@sapo.pt> wrote:
>
> Hello,
>
> My understanding of the problem is different, the files' first row is
> not tabular data, I might be wrong but it seems to me that it's
> something like
>
> first row [of] file1.txt [is]:
> abc.txt
>
> file2.txt:
> bed.txt
>
> etc.
>
> That's why the sapply loop reads one datum only and exits.
>
> Hope this helps,
>
> Rui Barradas
>
> Às 02:29 de 17/09/2022, Ebert,Timothy Aaron escreveu:
> > The syntax might not be quite right, but why not something like
> file.rename(colnames(dataframe)[1]) -- Using colnames to get the names of
> the columns that are in the first row, selecting the first element from
> colnames() and setting the file name equal to that.
> >
> > Do a for loop using current file names in some folder, and save to a new
> folder.
> >
> > Tim
> >
> > -----Original Message-----
> > From: R-help <r-help-boun...@r-project.org> On Behalf Of Kai Yang via
> R-help
> > Sent: Friday, September 16, 2022 1:52 PM
> > To: R-help Mailing List <r-help@r-project.org>; Rui Barradas <
> ruipbarra...@sapo.pt>
> > Subject: Re: [R] rename files in R
> >
> > [External Email]
> >
> > Hello,Here is the example:
> > file name first row file1.txt abc.txt file2.txt bed.txt
> file3.txt gogo.txt . . file1243.txt last.txt
> > I want to use loop because I need to read the first row information for
> first file, and then rename the file, then go to next file. I'm not sure if
> this is right way to approach my goal. Any suggestion will be appreciated.
> Thanks, Kai On Friday, September 16, 2022 at 10:38:32 AM PDT, Rui
> Barradas <ruipbarra...@sapo.pt> wrote:
> >
> > Hello,
> >
> > Please post the first row of 2 or 3 files and the expected result.
> >
> > You can rename files with ?file.rename. This function is vectorized its
> on arguments so you do not need a loop, only the source and destination
> filenames. Both vectors should have the same length, if not strange things
> will occur including data loss.
> >
> > Hope this helps,
> >
> > Rui Barradas
> >
> > Às 18:26 de 16/09/2022, Kai Yang via R-help escreveu:
> >> Hello,I have a lot of files with not meaningful name, such as:
> >> file1.txt, file2.txt ...... I need to rename them using the
> >> information from the first row of the files. Now I can get the
> >> information from the first row of each file. Now, I need know how to
> >> rename them in R (using loop?). Thank you for your helpKai
> >>
> >>
> >> [[alternative HTML version deleted]]
> >>
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