Hello,
I will run the examples below with the following data:
x <- c("12:00", "12:15", "12:30", "12:45", "13:00", "13:15", "13:30",
"13:45", "14:00", "14:15", "14:30", "14:45", "15:00", "15:15",
"15:30", "15:45", "16:00", "16:15", "16:30", "16:45", "17:00",
"17:15", "17:30", "17:45", "18:00")
b <- data.frame(time = x, myvar = sin(2*pi*seq_along(x)/length(x)))
Are they are saying is true, the vector b$myvar is a character vector
and that's what is being displayed.
In what follows I will first give examples of base graphics. The times
are first coerced to a proper time class with package chron.
library(chron)
b$time <- as.times(b$time)
# see ?plot.default for the meaning of
# argument 'type'
plot(myvar ~ time, b)
plot(myvar ~ time, b, type = "l")
plot(myvar ~ time, b, type = "b")
With ggplot2, there is no need to load a date/time class package, R can
do it with ?as.POSXct but the labels are datetime_breaks and
datetime_labels.
library(ggplot2)
b |>
dplyr::mutate(time = paste(Sys.Date(), time),
time = as.POSIXct(time)) |>
ggplot(aes(time, myvar)) +
geom_line() +
geom_point() +
scale_x_datetime(date_breaks = "1 hour", date_labels = "%H:%M") +
theme_bw()
Hope this helps,
Rui Barradas
Às 01:56 de 19/09/2022, Parkhurst, David escreveu:
I have a dataframe obtained using read.csv from an excel file. Its first
column is times, running from 18:00 to 19:30. If I want to plot other columns
against time, do I need to convert those somehow, and how would I do that?
If I run plot(b$time,b$myvar) I get a decent plot, but a friend suggests that R
is just treating those numbers as text, and putting them in alphabetical order.
True?
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