Hi.
On Wed, Jul 23, 2008 at 9:23 AM, Chris82 <[EMAIL PROTECTED]> wrote:
>
> Hello,
>
> I have a problem to flip a 200x200 matrix, which is imported by a .asc file.
> I want to flip the matrix like in a created example below:
>
>> b <- matrix(1:9,3,3,byrow=T)
>> b
>
> [,1] [,2] [,3]
> [1,] 1 2 3
> [2,] 4 5 6
> [3,] 7 8 9
>
>> b1 <- apply(t(b),1,rev)
>
>> b1
> [,1] [,2] [,3]
> [1,] 7 8 9
> [2,] 4 5 6
> [3,] 1 2 3
>
Your flip is nothing but reordering the rows, so your apply(...) is a
bit overkill. This can be done as:
X <- matrix(1:9, nrow=3, ncol=3, byrow=TRUE);
print(X);
Y <- X[nrow(X):1,];
print(Y);
This does also work for data frames:
Z <- as.data.frame(X);
Z <- Z[nrow(Z):1,];
print(Y);
> but my R Script doesn't work so. I don't know where the problem is.
> What's the different between a created matrix and a imported matrix?
>
> Here is my r Script:
>
> a <- read.table("c:/Test/Test.asc", header=FALSE, sep=" ")
> dim(a)
> b <- matrix(a, nrow=200, byrow=TRUE)
> d <- apply(t(b),1,rev)
> write.table(d, file = "c:/Test/output.asc", sep = " ", row.names = FALSE,
> col.names = FALSE)
Your mistake is most likely that you use byrow=TRUE, which results in
placing the *first column* of data.frame read by read.table() into the
*first row* of the matrix, and so on. Have you looked what 'a' and
'b' looks like? I guess that when you look at 'b' it is not what you
expect.
Your probably better off by just reordering the rows as suggested above.
Cheers
Henrik
>
> My output ist like this
>
> input:
>
> 1 2 3
> 4 5 6
> 7 8 9
>
> output:
>
> 3 2 1
> 6 5 4
> 9 8 7
>
> but it should be like this, as in the example:
>
> 7 8 9
> 4 5 6
> 1 2 3
>
> thanks.
> --
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> http://www.nabble.com/Flip-Matrix-form-file--tp18614800p18614800.html
> Sent from the R help mailing list archive at Nabble.com.
>
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>
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