As noted, this is not the place to ask about dplyr but the answer you may
want is perhaps straight R.
If you have a list called weekdays and you know you o not want to take the
fifth, then indexing with -5 removes it:
> weekdays <- list("Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat")
> weekdays[-5]
[[1]]
[1] "Sun"
[[2]]
[1] "Mon"
[[3]]
[1] "Tue"
[[4]]
[1] "Wed"
[[5]]
[1] "Fri"
[[6]]
[1] "Sat"
In general, any function you use to get one or more indices can be used sort
of like this:
> odder <- seq(from=1, to=length(weekdays), by=2)
> weekdays[-odder]
[[1]]
[1] "Mon"
[[2]]
[1] "Wed"
[[3]]
[1] "Fri"
So do you need to really search for dplyr functionality, such as how to take
all but some in a list in a pipeline. use the odd function `[` to access
the subset.
> weekdays %>% `[`(-5)
[[1]]
[1] "Sun"
[[2]]
[1] "Mon"
[[3]]
[1] "Tue"
[[4]]
[1] "Wed"
[[5]]
[1] "Fri"
[[6]]
[1] "Sat"
> weekdays %>% `[`(odder)
[[1]]
[1] "Sun"
[[2]]
[1] "Tue"
[[3]]
[1] "Thu"
[[4]]
[1] "Sat"
-----Original Message-----
From: R-help <r-help-boun...@r-project.org> On Behalf Of Christopher W. Ryan
via R-help
Sent: Thursday, November 18, 2021 4:40 PM
To: R-help@r-project.org
Subject: [R] the opposite of pluck() in purrr
I've just learned about pluck() and chuck() in the purrr package. Very cool!
As I understand it, they both will return one element of a list, either by
name or by [[]] index, or even "first" or "last"
I was hoping to find a way to return all *but* one specified element of a
list. Speaking loosely, pluck(-1) or pluck(!1) or !pluck(1), but none of
those of course work. Thinking of English language, I had hopes for
chuck(1) as in "chuck element 1 away, leaving the rest" but that's now how
it works.
Any tidyverse-centric ways to return all except one specified element of a
list?
Thanks.
--Chris Ryan
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
