Seems trivial enough Elizabeth, either using a matrix or data.frame.
R is vectorized mostly so A[,1] notation selects a column all at once. Your
condition is thus:
A[,1] == B[,1]
After using your sample data to initialize an A and a B, I get this:
> A[,1] == B[,1]
[1] FALSE FALSE FALSE TRUE TRUE TRUE TRUE TRUE TRUE
That Boolean vector can be used to index either of your matrices or any that
have the same number of rows:
Here is one solution using the vectorized ifelse() function:
using <- A[,1] == B[,1]
C <- A
C[, 2 ] <- ifelse(using, B[, 2], A[, 2])
I show the results below and you can tell us if that matches your need on
this sample data:
> A
[,1] [,2]
[1,] 12 NA
[2,] 12 NA
[3,] 12 NA
[4,] 13 NA
[5,] 13 NA
[6,] 13 NA
[7,] 14 NA
[8,] 14 NA
[9,] 14 NA
> B
[,1] [,2]
[1,] 11 6
[2,] 11 7
[3,] 11 8
[4,] 13 9
[5,] 13 10
[6,] 13 11
[7,] 14 12
[8,] 14 13
[9,] 14 14
> C
[,1] [,2]
[1,] 12 NA
[2,] 12 NA
[3,] 12 NA
[4,] 13 9
[5,] 13 10
[6,] 13 11
[7,] 14 12
[8,] 14 13
[9,] 14 14
Of course, the above can be done in fewer steps or many other ways.
-----Original Message-----
From: R-help <r-help-boun...@r-project.org> On Behalf Of Eliza Botto
Sent: Wednesday, September 1, 2021 5:00 PM
To: r-help@r-project.org
Subject: [R] conditional replacement of elements of matrix with another
matrix column
deaR useRs,
I have the matrix "A" and matrix "B" and I want the matrix "C". Is there a
way of doing it?
> dput(A)
structure(c(12, 12, 12, 13, 13, 13, 14, 14, 14, NA, NA, NA, NA, NA, NA, NA,
NA, NA), .Dim = c(9L, 2L))
> dput(B)
structure(c(11, 11, 11, 13, 13, 13, 14, 14, 14, 6, 7, 8, 9, 10, 11, 12, 13,
14), .Dim = c(9L, 2L))
> dput(C)
structure(c(12, 12, 12, 13, 13, 13, 14, 14, 14, NA, NA, NA, 9, 10, 11, 12,
13, 14), .Dim = c(9L, 2L))
Precisely, I want to replace the elements of 2nd column of A with those of B
provided the elements of 1st column match. Is there a single line loop or
code for that?
Thanks in advance,
Eliza Botto
[[alternative HTML version deleted]]
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