Thanks for providing a reproducible example! On Mon, 9 Aug 2021 15:33:53 +0200 Luigi Marongiu <marongiu.lu...@gmail.com> wrote:
> df[df[['vect[2]']] == 2, 'vect[2]'] <- "No" Please don't quote R expressions that you want to evaluate. 'vect[2]' is just a string, like 'hello world' or 'I want to create a new column named "vect[2]" instead of accessing the second one'. > Error in `[<-.data.frame`(`*tmp*`, df[[vect[2]]] == 2, vect[2], value > = "No") : missing values are not allowed in subscripted assignments > of data frames Since df[[2]] containts NAs, comparisons with it also contain NAs. While it's possible to subset data.frames with NAs (the rows corresponding to the NAs are returned filled with NAs of corresponding types), assignment to undefined rows is not allowed. A simple way to remove the NAs and only leave the cases where df[[vect[2]]] == 2 is TRUE would be to use which(). Compare: df[df[[vect[2]]] == 2,] df[which(df[[vect[2]]] == 2),] -- Best regards, Ivan ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
