Hello, I am using a large spreadsheet (over 600 variables). I tried `str` to check the dimensions of the spreadsheet and I got ``` > (str(df)) 'data.frame': 302 obs. of 626 variables: $ record_id : int 1 1 1 1 1 1 1 1 1 1 ... .... $ v1_medicamento___aceta : int 1 NA NA NA NA NA NA NA NA NA ... [list output truncated] NULL ``` I understand that `[list output truncated]` means that there are more variables than those allowed by str to be displayed as rows. Thus I increased the row's output with: ```
> (str(df, list.len=1000)) 'data.frame': 302 obs. of 626 variables: $ record_id : int 1 1 1 1 1 1 1 1 1 1 ... ... NULL ``` Does `NULL` mean that some of the variables are not closed? (perhaps a missing comma somewhere) Is there a way to check the sanity of the data and avoid that some separator is not in the right place? Thank you -- Best regards, Luigi ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.