On 24/07/2021 5:40 p.m., Rui Barradas wrote:
Hello,
No, it's not possible to work with a matrix in ggplot2.
Not even with an object of class "list".
If that's the main thing Jeff is doing, then he should convert to a
dataframe. But it *is* possible to work with the original matrix in
ggplot2, just not very natural:
l <- list(x=1:5, y=1:5)
d <- as.data.frame(l)
m <- as.matrix(d)
library(ggplot2)
ggplot(l, aes(x, y)) + geom_point() # Error
ggplot(d, aes(x, y)) + geom_point() # OK, as expected
ggplot(m, aes(x, y)) + geom_point() # Error
ggplot(NULL, aes(x=m[,"x"], y=m[,"y"])) + geom_point() # OK
Duncan Murdoch
Hope this helps,
Rui Barradas
Às 22:31 de 24/07/21, Jeff Reichman escreveu:
Duncan
I need to plot the results (ggplot2) and I'm thinking I can only use a data.frame object
in ggplot2. It is a rath r large "list" over 1 million rows. It is possible to
work with a matrix in ggplot2?
Jeff
-----Original Message-----
From: Duncan Murdoch <murdoch.dun...@gmail.com>
Sent: Saturday, July 24, 2021 12:03 PM
To: reichm...@sbcglobal.net; R-help@r-project.org
Subject: Re: [R] Converting a list to a data frame
Others have shown you how to extract the matrix and convert it to a dataframe.
My only addition is to suggest that you don't do this:
matrix methods are often much more efficient than dataframe methods, so if you
can work with the matrix without conversion, you'll often find things run a lot
faster.
Duncan Murdoch
On 24/07/2021 9:18 a.m., Jeff Reichman wrote:
How does one convert a list into a data frame?
str(weight_chains)
List of 1
$ : 'mcmc' num [1:100000, 1:3] -105 -105 -105 -104 -103 ...
..- attr(*, "dimnames")=List of 2
.. ..$ : NULL
.. ..$ : chr [1:3] "a" "b" "s"
..- attr(*, "mcpar")= num [1:3] 1001 101000 1
- attr(*, "class")= chr "mcmc.list"
Such that ..
weight_chains
a b s
1 -104.72512 1.0141407 9.369227
2 -104.52297 1.0167432 9.131354
3 -104.72669 1.0139528 9.219877
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______________________________________________
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