plot(sin, to=pi) # also works but with x labeled in radians.
# With x axis labeled in degrees
plot(sin, to=pi, axes=FALSE)
axis(2)
lbls <- seq(0, 180, 30)
axis(1, pi*lbls/180, lbls)
This can probably be done in ggplot2, but I don't know how off the
top of my head.
Hope this helps.
Spencer
On 7/24/21 2:04 PM, Eric Berger wrote:
Alternatively with base graphics
N <- 500 ## number of points (arbitrary)
degrees <- seq(from=0,to=180,length=N)
degreesToRadians <- function(d) { pi * d / 180.0} ## vectorIzed!
plot(x=degrees,y=sin(degreesToRadians(degrees)),type='l',
xlab="x",ylab="sin(x)",main="sin(x) vs x\nx is in degrees")
On Sat, Jul 24, 2021 at 9:52 PM Sorkin, John <jsor...@som.umaryland.edu>
wrote:
Try something like the following
copdat$degrees <- c(1:180)
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On Jul 24, 2021, at 2:41 PM, Thomas Subia via R-help <r-help@r-project.org>
wrote:
Colleagues,
Here is my code which plots sin(x) vs x, for angles between 0 and 180
degrees.
library(ggplot2)
library(REdaS)
copdat$degrees <- c(0,45,90,135,180)
copdat$radians <- deg2rad(copdat$degrees)
copdat$sin_x <- sin(copdat$radians)
ggplot(copdat,aes(x=degrees,y=sin_x))+
geom_point(size = 2)+ geom_line()+
theme_cowplot()+xlab("x")+
ylab("sin(x)")+
scale_x_continuous(breaks=seq(0,180,30))+
ggtitle("sin(x) vs x\nx is in degrees")
My trig students would prefer a curved line plot similar to what can be
plotted with Excel smooth line functionality.
I wanted to provide a relatively simple R script using ggplot to do this
without having to resort to fitting a sine curve to these points.
Some guidance would be appreciated.
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