You would need to loop through the list to use strsplit() -- you are
confused about list structure.
Here's a simple way to do it using regex's -- **assuming that there is
only one period in your names that delineates the extension.** If this
is not true, then this **will fail**. This is vectorized and so will
be more efficient than looping.
d <- data.frame (fn = c("name1.csv", "name2.txt"))
d
d$first <- sub("\\..+","",d$fn)
d
Cheers,
Bert
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Wed, Jul 7, 2021 at 6:28 PM Kai Yang via R-help <r-help@r-project.org> wrote:
>
> Hello List,
> I have a one column data frame to store file name with extension. I want to
> create new column to keep file name only without extension.
> I tried to use strsplit("name1.csv", "\\.")[[1]] to do that, but it just
> retain the first row only and it is a vector. how can do this for all of
> rows and put it into a new column?
> thank you,
> Kai
>
>
>
>
> [[alternative HTML version deleted]]
>
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