Hello,
Right, thanks. I should be
xx$I <- ave(xx$NUMBER_OF_YEARS, xx$COMPANY_NUMBER, FUN = function(x){
c(rep(1, length(x) - 1), length(x)) ### ???
})
Hope this helps,
Rui Barradas
Às 19:46 de 30/04/21, Bert Gunter escreveu:
There is something wrong here I believe -- see inline below:
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Fri, Apr 30, 2021 at 10:37 AM Rui Barradas <ruipbarra...@sapo.pt
<mailto:ruipbarra...@sapo.pt>> wrote:
Hello,
For column J, ave/seq_along seems to be the simplest. For column I, ave
is also a good option, it avoids split/lapply.
xx$I <- ave(xx$NUMBER_OF_YEARS, xx$COMPANY_NUMBER, FUN = function(x){
c(rep(1, length(x) - 1), max(length(x))) ### ???
})
**********
length() returns a single integer, so max(length(x)) makes no sense
************************************
xx$J <- ave(xx$NUMBER_OF_YEARS, xx$COMPANY_NUMBER, FUN = seq_along)
Hope this helps,
Às 11:49 de 30/04/21, PIKAL Petr escreveu:
> Hallo,
>
> Sorry, my suggestion did not worked in your case correctly as
split used
> natural factor ordering.
>
> So using Jim's data, this results in desired output.
>
> #prepare factor in original ordering
> ff <- factor(xx[,1], levels=unique(xx[,1]))
> lll <- split(xx$COMPANY_NUMBER, ff)
> xx$I <- unlist(lapply(lll, function(x) c(rep(1, length(x)-1),
> max(length(x)))),use.names=FALSE)
> xx$J <- unlist(lapply(lll, function(x) 1:length(x)), use.names=FALSE)
>> xx
> COMPANY_NUMBER NUMBER_OF_YEARS I J
> 1 70837 3 1 1
> 2 70837 3 1 2
> 3 70837 3 3 3
> 4 1000403 4 1 1
> 5 1000403 4 1 2
> 6 1000403 4 1 3
> 7 1000403 4 4 4
> 8 10029943 3 1 1
> 9 10029943 3 1 2
> 10 10029943 3 3 3
> 11 10037980 4 1 1
> 12 10037980 4 1 2
> 13 10037980 4 1 3
> 14 10037980 4 4 4
> 15 10057418 3 1 1
> 16 10057418 3 1 2
> 17 10057418 3 3 3
> 18 1009550 4 1 1
> 19 1009550 4 1 2
> 20 1009550 4 1 3
> 21 1009550 4 4 4
>
> Cheers.
> Petr
>
>> -----Original Message-----
>> From: R-help <r-help-boun...@r-project.org
<mailto:r-help-boun...@r-project.org>> On Behalf Of Jim Lemon
>> Sent: Friday, April 30, 2021 11:45 AM
>> To: e-mail ma015k3113 <ma015k3...@blueyonder.co.uk
<mailto:ma015k3...@blueyonder.co.uk>>; r-help mailing list
>> <r-help@r-project.org <mailto:r-help@r-project.org>>
>> Subject: Re: [R] Help understanding loop behaviour
>>
>> Hi email,
>> If you want what you described, try this:
>>
>> xx<-read.table(text="COMPANY_NUMBER NUMBER_OF_YEARS
>> 0070837 3
>> 0070837 3
>> 0070837 3
>> 1000403 4
>> 1000403 4
>> 1000403 4
>> 1000403 4
>> 10029943 3
>> 10029943 3
>> 10029943 3
>> 10037980 4
>> 10037980 4
>> 10037980 4
>> 10037980 4
>> 10057418 3
>> 10057418 3
>> 10057418 3
>> 1009550 4
>> 1009550 4
>> 1009550 4
>> 1009550 4",
>> header=TRUE,stringsAsFactors=FALSE)
>> xx$I<-NA
>> xx$J<-NA
>> row_count<-1
>> for(row in 1:nrow(xx)) {
>> if(row == nrow(xx) ||
>> xx$COMPANY_NUMBER[row]==xx$COMPANY_NUMBER[row+1]) {
>> xx$I[row]<-1
>> xx$J[row]<-row_count
>> row_count<-row_count+1
>> } else {
>> xx$I[row]<-xx$J[row]<-xx$NUMBER_OF_YEARS[row]
>> row_count<-1
>> }
>> }
>> xx
>>
>> Like Petr, I am assuming that you want company 10057418 treated
the same
>> as the others. If not, let us know why. I am also adssuming that
the first
> three
>> rows should _not_ have a "#" at the beginning, which means that
they will
> be
>> discarded.
>>
>> Jim
>>
>> On Fri, Apr 30, 2021 at 1:41 AM e-mail ma015k3113 via R-help
<r-help@r-
>> project.org <http://project.org>> wrote:
>>>
>>> I am trying to understand how loops in operate. I have a simple
>>> dataframe xx which is as follows
>>>
>>> COMPANY_NUMBER NUMBER_OF_YEARS
>>>
>>> #0070837 3
>>> #0070837 3
>>> #0070837 3
>>> 1000403 4
>>> 1000403 4
>>> 1000403 4
>>> 1000403 4
>>> 10029943 3
>>> 10029943 3
>>> 10029943 3
>>> 10037980 4
>>> 10037980 4
>>> 10037980 4
>>> 10037980 4
>>> 10057418 3
>>> 10057418 3
>>>
>>> 10057418 3
>>> 1009550 4
>>> 1009550 4
>>> 1009550 4
>>> 1009550 4
>>> The code I have written is
>>>
>>> while (i <= nrow(xx1) )
>>>
>>> {
>>>
>>> for (j in 1:xx1$NUMBER_OF_YEARS[i])
>>> {
>>> xx1$I[i] <- i
>>> xx1$J[j] <- j
>>> xx1$NUMBER_OF_YEARS_j[j] <- xx1$NUMBER_OF_YEARS[j] } i=i +
>>> (xx1$NUMBER_OF_YEARS[i] ) } After running the code I want my
>> dataframe
>>> to look like
>>>
>>> |COMPANY_NUMBER |NUMBER_OF_YEARS| | I| |J|
>>>
>>> |#0070837 |3| |1| |1|
>>> |#0070837 |3| |1| |2|
>>> |#0070837 |3| |3| |3|
>>> |1000403 |4| |1| |1|
>>> |1000403 |4| |1| |2|
>>> |1000403 |4| |1| |3|
>>> |1000403 |4| |4| |4|
>>> |10029943 |3| |1| |1|
>>> |10029943 |3| |1| |2|
>>> |10029943 |3| |3| |3|
>>> |10037980 |4| |1| |1|
>>> |10037980 |4| |1| |2|
>>> |10037980 |4| |1| |3|
>>> |10037980 |4| |4| |4|
>>> |10057418 |3| |1| |1|
>>> |10057418 |3| |1| |1|
>>> |10057418 |3| |1| |1|
>>> |1009550 |4| |1| |1|
>>> |1009550 |4| |1| |2|
>>> |1009550 |4| |1| |3|
>>> |1009550 |4| |4| |4|
>>>
>>>
>>> I get the correct value of I but in the wrong row but the vaule
of J
>>> is correct in the first iteration and then it goes to 1
>>>
>>> Any help will be greatly appreciated
>>> [[alternative HTML version deleted]]
>>>
>>> ______________________________________________
>>> R-help@r-project.org <mailto:R-help@r-project.org> mailing list
-- To UNSUBSCRIBE and more, see
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>>> PLEASE do read the posting guide
>>> http://www.R-project.org/posting-guide.html
<http://www.R-project.org/posting-guide.html>
>>> and provide commented, minimal, self-contained, reproducible code.
>>
>> ______________________________________________
>> R-help@r-project.org <mailto:R-help@r-project.org> mailing list
-- To UNSUBSCRIBE and more, see
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>> PLEASE do read the posting guide
http://www.R-project.org/posting- <http://www.R-project.org/posting->
>> guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>> ______________________________________________
>> R-help@r-project.org <mailto:R-help@r-project.org> mailing list
-- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
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>> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
<http://www.R-project.org/posting-guide.html>
>> and provide commented, minimal, self-contained, reproducible code.
______________________________________________
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To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
<http://www.R-project.org/posting-guide.html>
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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