Hello,
The plots that you say give bars (or my equivalent version below) don't
give bars, what they give are boxplots with just one value and the
median Q1 and Q3 are all equal.
plot(y ~ factor(x), df, pch = 16) # boxplot
Is the following what you are looking for?
plot(y ~ as.integer(factor(x)), df, pch = 16, xlab = "x", xaxt = "n")
axis(1, at = as.integer(factor(df$x)), labels = df$x)
Hope this helps,
Rui Barradas
Às 13:16 de 27/08/20, Luigi Marongiu escreveu:
Hello,
I have a dataframe as follows:
```
x = c("0 pmol", "10 pmol", "100 pmol", "1000 pmol")
y = c(0.9306, 1.8906, 2.2396, 2.7917)
df = data.frame(x, y)
str(df)
'data.frame': 4 obs. of 2 variables:
$ x: chr "0 pmol" "10 pmol" "100 pmol" "1000 pmol"
$ y: num 0.931 1.891 2.24 2.792
```
I would like to visualize the data with the classic dots (pch=16) but:
```
plot(df$y ~ df$x)
Error in plot.window(...) : need finite 'xlim' values
In addition: Warning messages:
1: In xy.coords(x, y, xlabel, ylabel, log) : NAs introduced by coercion
2: In min(x) : no non-missing arguments to min; returning Inf
3: In max(x) : no non-missing arguments to max; returning -Inf
```
which is right because x is not numeric, so I took the factor:
```
plot(df$y ~ factor(df$x)) # gives bars instead of dots
plot(df$y ~ factor(df$x), pch = 16) # this also
```
I tried to convert directly the dataframe:
```
df$x = lapply(df$x, factor)
str(df)
'data.frame': 4 obs. of 2 variables:
$ x:List of 4
..$ : Factor w/ 1 level "0 pmol": 1
..$ : Factor w/ 1 level "10 pmol": 1
..$ : Factor w/ 1 level "100 pmol": 1
..$ : Factor w/ 1 level "1000 pmol": 1
$ y: num 0.931 1.891 2.24 2.792
plot(r$y ~ r$x, pch = 16)
Error in plot.window(...) : need finite 'xlim' values
In addition: Warning messages:
1: In xy.coords(x, y, xlabel, ylabel, log) : NAs introduced by coercion
2: In min(x) : no non-missing arguments to min; returning Inf
3: In max(x) : no non-missing arguments to max; returning -Inf
```
If I try to pass the number of levels:
```
plot(df$y ~ factor(df$x, 1:4), pch = 16) # this draw a boxplot with
all data on level 1
df$x = lapply(df$x, factor(1:4))
Error in match.fun(FUN) :
'factor(1:4)' is not a function, character or symbol
```
Since the transformation has given only one level (1), my questions are:
How do I tell R to use a dot instead of a line?
What is the correct way of setting factors?
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