Hi!
How about this?
--- snip ---
> x <- c("STRING 01. Remainder of the string","STR ING 01. Remainder
of the string","STRIN G 01. Remainder of the string","STR IN G
01. Remainder of the string")
> x1<-unlist(strsplit(x,"\\."))
> for (i in seq(1,length(x1),2)) { x[(i+1) %/% 2]<-paste(gsub("
","",x1[i]),x1[i+1],sep=".") }
> x
[1] "STRING01. Remainder of the string" "STRING01. Remainder of the
string" "STRING01. Remainder of the string"
[4] "STRING01. Remainder of the string"
--- snip ---
Or do I miss something?
Best,
Kimmo
ti, 2020-07-28 kello 17:19 -0700, Dennis Fisher kirjoitti:
> Richard
>
> In reply to your “first response”, the text was originally in a Word
> document and it did NOT contain the errant spaces. I used read_docx
> in the textreadr package to access the text. The spaces were added
> during that step. I am copying the maintainer of that package to see
> if he has any idea as to the source.
>
> Thanks for your regular expression suggestion.
>
> Dennis
>
>
> Dennis Fisher MD
> P < (The "P Less Than" Company)
> Phone / Fax: 1-866-PLessThan (1-866-753-7784)
> www.PLessThan.com <http://www.plessthan.com/>
>
>
>
>
> > On Jul 28, 2020, at 5:11 PM, Richard O'Keefe <rao...@gmail.com>
> > wrote:
> >
> > The first response has to be "how did the spaces get there
> > in the first place?" Can you fix the process that creates
> > the data? If the process sometimes generates one extra
> > space, are you sure it never generates two?
> >
> > But let's treat this purely as a regular expression
> > problem, where if there is a space before a dot you want
> > to delete the first. In vi(1) you would do
> >
> > s/^\([^ .]*\) \([^.]*\)/\1\2/
> >
> > but apparently there is *supposed* to be a space before
> > the 01, so it is only when there are two or more spaces
> > that one should be deleted, so we'd want
> >
> > s/^\([^ .]*\) \([^ .]* \)/\1\2/
> >
> > I leave converting that to R as an exercise for the reader.
> >
> >
> >
> >
> > On Wed, 29 Jul 2020 at 08:20, Dennis Fisher <fis...@plessthan.com
> > <mailto:fis...@plessthan.com>> wrote:
> > R 4.0.2
> > OS X
> >
> > Colleagues
> >
> > I have strings that contain a space in an unexpected location. The
> > intended string is:
> > “STRING 01. Remainder of the string"
> > However, variants are:
> > “STR ING 01. Remainder of the string"
> > “STRIN G 01. Remainder of the string"
> >
> > I would like a general approach to deleting a space, but only if it
> > appears before the period. Any suggestions on a regular expression
> > for this?
> >
> > Dennis
> >
> > Dennis Fisher MD
> > P < (The "P Less Than" Company)
> > Phone / Fax: 1-866-PLessThan (1-866-753-7784)
> > www.PLessThan.com <http://www.plessthan.com/> <
> > http://www.plessthan.com/ <http://www.plessthan.com/>>
> >
> >
> >
> >
> >
> > [[alternative HTML version deleted]]
> >
> > ______________________________________________
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> > PLEASE do read the posting guide
> > http://www.R-project.org/posting-guide.html <
> > http://www.r-project.org/posting-guide.html>
> > and provide commented, minimal, self-contained, reproducible code.
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
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> PLEASE do read the posting guide
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