Were you thinking of the %<>% operator? That's a magrittr thing, where
x %<>% y acts like x <- x %>% y .
Duncan Murdoch
On 25/07/2020 4:18 p.m., Patrick (Malone Quantitative) wrote:
Oh, right--I puzzled out my mistake.
On Sat, Jul 25, 2020 at 4:17 PM Jeff Newmiller <jdnew...@dcn.davis.ca.us>
wrote:
False. Mutate is similar in structure to the base function `within`. Which
is why you have to assign the altered data frame back onto itself.
On July 25, 2020 12:59:06 PM PDT, "Patrick (Malone Quantitative)" <
mal...@malonequantitative.com> wrote:
Jeff,
mutate(), which is I think part of dplyr, also violates this, for what
it's
worth. I suspect the breaking point is that mutate() is intended to
create
new columns in the dataframe, not alter existing ones.
On Sat, Jul 25, 2020 at 3:52 PM Jeff Newmiller
<jdnew...@dcn.davis.ca.us>
wrote:
R is largely a functional language. You do something to an input and
end
up with an output that has no effect on the input. This is actually a
highly desirable feature.
If you want your df variable to reflect changes made then you need
to
assign your result back into it.
df <- df %>% mutate(v1 = as.double(v1))
(Note that the data.table package violates this principle and is
controversial as a result.)
On July 25, 2020 12:11:24 PM PDT, H <age...@meddatainc.com> wrote:
In a statement like:
df %>% mutate(v1 = as.double(v1))
I expect the variable v1 in dataframe df to have been converted into
a
double. However, when I do:
str(df)
v1 still shows as int. Do I need to save the modified dataframe
after
mutating a variable?
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