Thank you all. Your suggestions worked. As you said, the problem appeared to 
have been the commas that were part of the data frame.

Thanks again 🙂
________________________________
From: Rui Barradas <ruipbarra...@sapo.pt>
Sent: Tuesday, April 21, 2020 9:38 PM
To: Helen Sawaya <helensaw...@hotmail.com>
Cc: Jim Lemon <drjimle...@gmail.com>; Michael Dewey <li...@dewey.myzen.co.uk>; 
r-help@R-project.org <r-help@r-project.org>
Subject: Re: [R] NA command in a 'for' loop

Hello,

Much better, you have "," at the end of your data elements so nothing is
working.

The following 3 instructions

1. remove those commas,
2. create a logical vector trying to guess which columns are numeric
3. coerce those columns to numeric.


d[] <- lapply(d, function(x){sub(",$", "", x)})
not_num <- sapply(d, function(x) all(is.na(as.numeric(as.character(x)))))
d[!not_num] <- lapply(d[!not_num], function(x) as.numeric(as.character(x)))



Then, if you want just d$V13 == 0 to become NA, this will do it.


is.na(d[["V13"]]) <- d[["V13"]] == 0


If you want to do this to all numeric columns, try


d[!not_num] <- lapply(d[!not_num], function(x){
   is.na(x) <- x == 0
   x
})


Hope this helps,

Rui Barradas


Ă€s 18:11 de 21/04/20, Helen Sawaya escreveu:
> Thank you for your patience.
>
> This is the output of dput(head(d, 10))
>
> structure(list(V1 = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
> 1L, 1L), .Label = "9.9761E+11,", class = "factor"), V2 = structure(c(1L,
> 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = "threat,", class = "factor"),
>      V3 = structure(c(1L, 28L, 37L, 48L, 55L, 63L, 73L, 88L, 2L,
>      20L), .Label = c("1,", "10,", "100,", "101,", "102,", "104,",
>      "107,", "108,", "109,", "110,", "111,", "112,", "113,", "114,",
>      "115,", "116,", "117,", "118,", "119,", "12,", "13,", "14,",
>      "15,", "16,", "17,", "18,", "19,", "2,", "20,", "21,", "22,",
>      "23,", "24,", "27,", "28,", "29,", "3,", "30,", "31,", "32,",
>      "33,", "34,", "35,", "36,", "37,", "38,", "39,", "4,", "42,",
>      "44,", "46,", "47,", "48,", "49,", "5,", "50,", "52,", "53,",
>      "54,", "55,", "57,", "59,", "6,", "60,", "61,", "62,", "63,",
>      "64,", "65,", "66,", "68,", "69,", "7,", "71,", "74,", "75,",
>      "76,", "78,", "81,", "82,", "83,", "84,", "85,", "86,", "87,",
>      "88,", "89,", "9,", "90,", "91,", "92,", "94,", "95,", "96,",
>      "97,", "98,"), class = "factor"), V4 = structure(c(1L, 2L,
>      1L, 2L, 2L, 2L, 2L, 2L, 1L, 1L), .Label = c("1,", "2,"), class = 
> "factor"),
>      V5 = structure(c(2L, 2L, 2L, 1L, 2L, 1L, 1L, 2L, 2L, 2L), .Label = 
> c("1,",
>      "2,"), class = "factor"), V6 = structure(c(2L, 1L, 2L, 2L,
>      1L, 2L, 2L, 1L, 2L, 2L), .Label = c("1,", "2,"), class = "factor"),
>      V7 = structure(c(2L, 1L, 2L, 2L, 2L, 2L, 1L, 2L, 1L, 2L), .Label = 
> c("1,",
>      "2,"), class = "factor"), V8 = structure(c(41L, 92L, 63L,
>      36L, 2L, 81L, 12L, 14L, 23L, 33L), .Label = c("abduction,",
>      "abortion,", "abuse,", "accident,", "addicted,", "agony,",
>      "anger,", "angry,", "anguish,", "assault,", "bankrupt,",
>      "bullet,", "burial,", "cancer,", "cemetery,", "coffin,",
>      "corpse,", "crash,", "crisis,", "cruel,", "death,", "defeated,",
>      "depressed,", "deserted,", "despair,", "destroy,", "disaster,",
>      "disloyal,", "distress,", "dreadful,", "drown,", "dull,",
>      "dump,", "emaciated,", "failure,", "fatigue,", "fault,",
>      "feeble,", "fever,", "filth,", "forlorn,", "germs,", "gloomy,",
>      "hardship,", "hell,", "helpless,", "horror,", "hostage,",
>      "hostile,", "hurt,", "idiot,", "infest,", "injury,", "irritable,",
>      "jail,", "killer,", "lonely,", "malaria,", "messy,", "misery,",
>      "mistake,", "morbid,", "murder,", "mutilate,", "pain,", "panic,",
>      "poison,", "prison,", "pus,", "rape,", "rat,", "rejected,",
>      "sad,", "scum,", "shame,", "sick,", "slap,", "snake,", "spider,",
>      "suicide,", "surgery,", "terrible,", "tormented,", "trash,",
>      "trauma,", "ugly,", "ulcer,", "unease,", "unhappy,", "useless,",
>      "victim,", "wasp,", "weep,", "worm,", "wound,"), class = "factor"),
>      V9 = structure(c(24L, 90L, 73L, 10L, 92L, 33L, 84L, 96L,
>      70L, 57L), .Label = c("alley,", "ankle,", "appliance,", "audience,",
>      "bandage,", "bathroom,", "bookcase,", "border,", "branch,",
>      "cabinet,", "category,", "clean,", "cliff,", "cold,", "consider,",
>      "consoled,", "context,", "country,", "crop,", "dentist,",
>      "detail,", "dinner,", "doctor,", "dynamic,", "easygoing,",
>      "elbow,", "energetic,", "farm,", "faucet,", "flat,", "flowing,",
>      "fork,", "freezer,", "glass,", "grass,", "guess,", "humble,",
>      "icebox,", "industry,", "invisible,", "jug,", "lighting,",
>      "lion,", "listen,", "little,", "machine,", "metal,", "month,",
>      "mushroom,", "napkin,", "news,", "noisy,", "north,", "nudge,",
>      "number,", "numerous,", "obey,", "odd,", "oval,", "plant,",
>      "possible,", "pot,", "public,", "puzzled,", "quarter,", "rational,",
>      "ready,", "reflect,", "reliable,", "repentant,", "sand,",
>      "school,", "secret,", "series,", "shark,", "shoe,", "shop,",
>      "shortened,", "skyline,", "stable,", "storm,", "stove,",
>      "table,", "theory,", "tower,", "truck,", "upgrade,", "upright,",
>      "utensil,", "vest,", "vision,", "volcano,", "walk,", "watchful,",
>      "window,", "winter,"), class = "factor"), V10 = structure(c(1L,
>      1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = "NA,", class = "factor"),
>      V11 = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = 
> "NA,", class = "factor"),
>      V12 = structure(c(2L, 1L, 2L, 2L, 2L, 2L, 1L, 2L, 1L, 2L), .Label = 
> c("203,",
>      "205,"), class = "factor"), V13 = structure(c(1L, 1L, 1L,
>      1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = "1,", class = "factor"),
>      V14 = c(4063L, 4914L, 1508L, 1819L, 1228L, 992L, 1898L, 1174L,
>      1294L, 1417L)), row.names = c(NA, 10L), class = "data.frame”)
>
> When I use the following:
>
> all.files <- list.files(".")
> txt.files <- grep("threat.txt",all.files,value=T)
>
> for(i in txt.files) {
>    d<-read.table(i, header=FALSE)
>    d[] <- lapply(d, function(x) {is.na(x) <- x == 0; x})
>    write.table(d,paste0(i, "trial.txt"), quote=FALSE, row.names=FALSE)}
>
> I get this (an example of one of the output files with zeros in V13):
>
> V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11 V12 V13 V14
> 3.17903E+11, threat, 1, 1, 2, 2, 1, useless, flowing, NA, NA, 203, 1, 949
> 3.17903E+11, threat, 3, 2, 2, 1, 1, hostage, skyline, NA, NA, 203, 1, 1116
> 3.17903E+11, threat, 4, 1, 1, 1, 2, messy, ready, NA, NA, 205, 1, 1277
> 3.17903E+11, threat, 6, 2, 1, 2, 2, emaciated, shortened, NA, NA, 205, 1, 691
> 3.17903E+11, threat, 7, 1, 1, 1, 1, abuse, plant, NA, NA, 203, 1, 660
> 3.17903E+11, threat, 8, 2, 1, 2, 2, tormented, easygoing, NA, NA, 205, 1, 812
> 3.17903E+11, threat, 9, 1, 2, 2, 2, hurt, sand, NA, NA, 205, 1, 917
> 3.17903E+11, threat, 10, 1, 1, 1, 1, surgery, freezer, NA, NA, 203, 1, 1829
> 3.17903E+11, threat, 12, 2, 2, 1, 2, accident, category, NA, NA, 205, 1, 821
> 3.17903E+11, threat, 13, 2, 1, 2, 2, terrible, energetic, NA, NA, 205, 1, 783
> 3.17903E+11, threat, 14, 1, 2, 2, 1, wound, storm, NA, NA, 203, 1, 813
> 3.17903E+11, threat, 15, 1, 1, 1, 2, victim, utensil, NA, NA, 205, 1, 1132
> 3.17903E+11, threat, 16, 2, 2, 1, 2, bankrupt, lighting, NA, NA, 203, 0, 1510
> 3.17903E+11, threat, 17, 1, 1, 1, 2, anguish, country, NA, NA, 203, 0, 811
> 3.17903E+11, threat, 18, 2, 2, 1, 1, snake, table, NA, NA, 203, 1, 805
> 3.17903E+11, threat, 19, 1, 1, 1, 2, slap, crop, NA, NA, 205, 1, 1180
> 3.17903E+11, threat, 20, 2, 1, 2, 2, scum, shoe, NA, NA, 205, 1, 792
> 3.17903E+11, threat, 21, 1, 2, 2, 1, weep, shop, NA, NA, 203, 1, 870
> 3.17903E+11, threat, 23, 2, 1, 2, 1, spider, border, NA, NA, 203, 1, 871
>
> str(d) gives me the following:
>
> 'data.frame': 96 obs. of  14 variables:
>   $ V1 : Factor w/ 1 level "9.9761E+11,": 1 1 1 1 1 1 1 1 1 1 ...
>   $ V2 : Factor w/ 1 level "threat,": 1 1 1 1 1 1 1 1 1 1 ...
>   $ V3 : Factor w/ 96 levels "1,","10,","100,",..: 1 28 37 48 55 63 73 88 2 
> 20 ...
>   $ V4 : Factor w/ 2 levels "1,","2,": 1 2 1 2 2 2 2 2 1 1 ...
>   $ V5 : Factor w/ 2 levels "1,","2,": 2 2 2 1 2 1 1 2 2 2 ...
>   $ V6 : Factor w/ 2 levels "1,","2,": 2 1 2 2 1 2 2 1 2 2 ...
>   $ V7 : Factor w/ 2 levels "1,","2,": 2 1 2 2 2 2 1 2 1 2 ...
>   $ V8 : Factor w/ 95 levels "abduction,","abortion,",..: 41 92 63 36 2 81 12 
> 14 23 33 ...
>   $ V9 : Factor w/ 96 levels "alley,","ankle,",..: 24 90 73 10 92 33 84 96 70 
> 57 ...
>   $ V10: Factor w/ 1 level "NA,": 1 1 1 1 1 1 1 1 1 1 ...
>   $ V11: Factor w/ 1 level "NA,": 1 1 1 1 1 1 1 1 1 1 ...
>   $ V12: Factor w/ 2 levels "203,","205,": 2 1 2 2 2 2 1 2 1 2 ...
>   $ V13: Factor w/ 1 level "1,": 1 1 1 1 1 1 1 1 1 1 ...
>   $ V14: int  4063 4914 1508 1819 1228 992 1898 1174 1294 1417 …
>
> When I use this:
>
> for(i in txt.files) {
>    d<-read.table(i, header=FALSE)
>    d2<-d[d$V13==1,]
>    write.table(d2,sub("[.]",".trial.",i),quote=FALSE,row.names=FALSE)
> }
>
> I get empty files:
>
> str(d2)
> 'data.frame': 0 obs. of  14 variables:
>   $ V1 : Factor w/ 1 level "9.9761E+11,":
>   $ V2 : Factor w/ 1 level "threat,":
>   $ V3 : Factor w/ 96 levels "1,","10,","100,",..:
>   $ V4 : Factor w/ 2 levels "1,","2,":
>   $ V5 : Factor w/ 2 levels "1,","2,":
>   $ V6 : Factor w/ 2 levels "1,","2,":
>   $ V7 : Factor w/ 2 levels "1,","2,":
>   $ V8 : Factor w/ 95 levels "abduction,","abortion,",..:
>   $ V9 : Factor w/ 96 levels "alley,","ankle,",..:
>   $ V10: Factor w/ 1 level "NA,":
>   $ V11: Factor w/ 1 level "NA,":
>   $ V12: Factor w/ 2 levels "203,","205,":
>   $ V13: Factor w/ 1 level "1,":
>   $ V14: int
>
> When I use as.integer to change V13 to an integer, the output of this column 
> is replaced by 1s and 2s..
>
>
>> On Apr 21, 2020, at 1:14 AM, Rui Barradas <ruipbarra...@sapo.pt> wrote:
>>
>> Hello,
>>
>> Thanks for the data. But since the replacements still do not work, please 
>> post the output of
>>
>> dput(head(d, 10))
>>
>>
>> in order for us to have an *exact* copy of the data structure.
>> I had asked for 20 or 30 rows but given your post 10 are enough.
>> With a way to exactly reproduce what you have, it will be much easier to try 
>> code and find a solution. I, and I believe most R users, will run
>>
>> str(d)
>>
>> as one of the first steps to know what is in that problem column. And go 
>> from there.
>>
>>
>> Hope this helps,
>>
>> Rui Barradas
>>
>> Às 04:52 de 21/04/20, Helen Sawaya escreveu:
>>> Thank you all for your input.
>>> This is an example of one data file (I have 74 data files):
>>> 2.90546E+11, threat,    1, 2, 1, 2, 1,        death,        stove,          
>>>   NA,           NA,  205,    0,  394
>>> 2.90546E+11, threat,    2, 2, 2, 1, 1,    emaciated,    shortened,          
>>>   NA,           NA,  205,    0,  502
>>> 2.90546E+11, threat,    3, 1, 1, 1, 2,     mutilate,     consider,          
>>>   NA,           NA,  205,    1,  468
>>> 2.90546E+11, threat,    6, 1, 2, 2, 1,         weep,         shop,          
>>>   NA,           NA,  203,    1,  345
>>> 2.90546E+11, threat,    9, 2, 1, 2, 2,    tormented,    easygoing,          
>>>   NA,           NA,  205,    1,  373
>>> 2.90546E+11, threat,   10, 1, 2, 2, 2,        snake,        table,          
>>>   NA,           NA,  205,    1,  343
>>> 2.90546E+11, threat,   11, 2, 2, 1, 1,       crisis,       faucet,          
>>>   NA,           NA,  203,    1,  437
>>> 2.90546E+11, threat,   12, 1, 1, 1, 1,       victim,      utensil,          
>>>   NA,           NA,  203,    1,  343
>>> 2.90546E+11, threat,   14, 1, 2, 2, 1,    depressed,    repentant,          
>>>   NA,           NA,  203,    1,  441
>>> 2.90546E+11, threat,   15, 2, 2, 1, 2,         scum,         shoe,          
>>>   NA,           NA,  205,    1,  475
>>> ​Column 13 has values of 0s and 1s which my cognitive task outputted. 
>>> Column 14 is the reaction time (ms) data. I want to get rid of the rows 
>>> that contain zeros so I thought I'd first replace zeros with NAs then use 
>>> complete.cases function to get rid of the NAs. I also wanted to apply other 
>>> functions so I included them all in a loop. All work fine except for the 
>>> one where I try to turn the zeros to NAs.
>>> Jim when I tried your mockdata example, it worked fine. But when I 
>>> translated it to my data, I still get zeros in the output. Can you identify 
>>> any mistranslations I'm doing?
>>> txt.files<-list.files(".",pattern="dotprobe") #all my data files are text 
>>> files in one folder
>>> for(tf in txt.files) {
>>>    d<-read.table(tf)
>>>    d[,13][d[,13]==0]<-NA #column 13 contains zeros
>>>    d<-d[ ,-c(10,11)] #get rid of columns 10 and 11
>>>    write.table(d,sub("[.]",".tlbs.",tf),quote=FALSE, row.names=FALSE)
>>> }
>>> That's an example of one of the output I get:
>>> V1 V2 V3 V4 V5 V6 V7 V8 V9 V12 V13 V14
>>> 2.90546E+11, threat, 1, 2, 1, 2, 1, death, stove, 205, 0, 394
>>> 2.90546E+11, threat, 2, 2, 2, 1, 1, emaciated, shortened, 205, 0, 502
>>> 2.90546E+11, threat, 3, 1, 1, 1, 2, mutilate, consider, 205, 1, 468
>>> 2.90546E+11, threat, 6, 1, 2, 2, 1, weep, shop, 203, 1, 345
>>> 2.90546E+11, threat, 9, 2, 1, 2, 2, tormented, easygoing, 205, 1, 373
>>> 2.90546E+11, threat, 10, 1, 2, 2, 2, snake, table, 205, 1, 343
>>> Columns 10 and 11 were deleted. But zeros were not replaced by NAs.
>>> After all the data cleaning, the functions I'm interested in including in 
>>> the loop are: get_tlbs and summarize_bias (and these also work fine in my 
>>> loop).
>>> Thanks again 🙂
>>> Sincerely
>>> Helen
>>> ------------------------------------------------------------------------
>>> *From:* Jim Lemon <drjimle...@gmail.com>
>>> *Sent:* Tuesday, April 21, 2020 2:52 AM
>>> *To:* Rui Barradas <ruipbarra...@sapo.pt>
>>> *Cc:* Helen Sawaya <helensaw...@hotmail.com>; Michael Dewey 
>>> <li...@dewey.myzen.co.uk>; r-help@R-project.org <r-help@r-project.org>
>>> *Subject:* Re: [R] NA command in a 'for' loop
>>> Hi Helen,
>>> Your problem may lie in using row.names=TRUE. I was puzzled when an
>>> extra column kept popping up in the output files. For reading in and
>>> replacing zeros with NAs, this seems to work:
>>> for(mockdata in 1:3) {
>>>   mdf<-data.frame(sample(2:20,10),sample(2:20,10),sample(0:1,10,TRUE))
>>>   write.table(mdf,file=paste0("threat",mockdata,".txt"),quote=FALSE,
>>>    row.names=FALSE,col.names=FALSE)
>>> }
>>> txt.files<-list.files(".",pattern="threat[1-3]")
>>> for(tf in txt.files) {
>>>   d<-read.table(tf)
>>>   d[,3][d[,3]==0]<-NA
>>>   write.table(d,sub("[.]",".tbls.",tf),quote=FALSE,row.names=FALSE)
>>> }
>>> Jim
>>> On Tue, Apr 21, 2020 at 7:57 AM Rui Barradas <ruipbarra...@sapo.pt> wrote:
>>>>
>>>> Hello,
>>>>
>>>> I believe the only way we have to see what is happening is for you to
>>>> post the output of
>>>>
>>>>
>>>> dput(head(d, 20))  # or 30
>>>>
>>>>
>>>> or, with d2 a subset of d that includes zeros,
>>>>
>>>>
>>>> dput(head(d2, 20))
>>>>
>>>>
>>>> Hope this helps,
>>>>
>>>> Rui Barradas
>>>>
>>>> Às 17:48 de 20/04/20, Helen Sawaya escreveu:
>>>>> I have one column that represents correct response versus error (correct
>>>>> is coded as 1 and error is coded as 0). Nowhere else in the dataset are
>>>>> there values of 0. The vector is treated as an integer.
>>>>> ------------------------------------------------------------------------
>>>>> *From:* Michael Dewey <li...@dewey.myzen.co.uk>
>>>>> *Sent:* Monday, April 20, 2020 7:35 PM
>>>>> *To:* Helen Sawaya <helensaw...@hotmail.com>; Rui Barradas
>>>>> <ruipbarra...@sapo.pt>; r-help@R-project.org <r-help@R-project.org>
>>>>> *Subject:* Re: [R] NA command in a 'for' loop
>>>>> Just a thought Helen but is x being treated as a real and what you think
>>>>> are zero and are printed as zero are in fact some very small number? If
>>>>> so you need to alter your test appropriately.
>>>>>
>>>>> Michael
>>>>>
>>>>> On 20/04/2020 17:25, Helen Sawaya wrote:
>>>>>> Thank you for your reply.
>>>>>>
>>>>>> I tried d[] <- lapply(d, function(x) {is.na(x) <- x == 0; x})
>>>>>> but I am still getting zeros instead of NAs in my output..
>>>>>>
>>>>>> I wonder if the problem is that some of my data files don't have any 
>>>>>> zeros (participants made no errors)..
>>>>>> ________________________________
>>>>>> From: Rui Barradas <ruipbarra...@sapo.pt>
>>>>>> Sent: Monday, April 20, 2020 9:05 AM
>>>>>> To: Helen Sawaya <helensaw...@hotmail.com>; r-help@R-project.org 
>>>>>> <r-help@R-project.org>
>>>>>> Subject: Re: [R] NA command in a 'for' loop
>>>>>>
>>>>>> Hello,
>>>>>>
>>>>>> Instead of
>>>>>>
>>>>>> d[d == 0] <- NA
>>>>>>
>>>>>> try
>>>>>>
>>>>>> d[] <- lapply(d, function(x) {is.na(x) <- x == 0; x})
>>>>>>
>>>>>>
>>>>>> Also, in the first for loop
>>>>>>
>>>>>> paste(i, sep = "")
>>>>>>
>>>>>> does nothing, it's the same as i.
>>>>>> And the same for
>>>>>>
>>>>>> (d2$V4 == 1) == TRUE
>>>>>>
>>>>>> Since (d2$V4 == 1)  already is FALSE/TRUE there is no need for
>>>>>>
>>>>>> (.) == TRUE
>>>>>>
>>>>>>
>>>>>> Hope this helps,
>>>>>>
>>>>>> Rui Barradas
>>>>>>
>>>>>>
>>>>>>
>>>>>> Às 20:52 de 19/04/20, Helen Sawaya escreveu:
>>>>>>> Dear R experts,
>>>>>>>
>>>>>>> I am using a 'for' loop to apply commands to multiple datasets (each 
>>>>>>> file is one participant). The only one not working is the command that 
>>>>>>> identifies zeros in my datasets and changes them to NAs. But when I 
>>>>>>> look at the output, zeros ("0") are still present. Surprisingly, the 
>>>>>>> functions work fine when I apply them to a single
>>>>> dataset (outside the loop). I've tried:
>>>>>>>
>>>>>>> all.files <- list.files(".")
>>>>>>> txt.files <- grep("threat.txt",all.files,value=T)
>>>>>>>
>>>>>>> for(i in txt.files){
>>>>>>>      d <- read.table(paste(i,sep=""),header=F)
>>>>>>>      d[d==0] <- NA #replace zeros with NA
>>>>>>>      write.table(d, paste0(i,".tlbs.txt"), quote=FALSE, row.names=TRUE)}
>>>>>>>      d<-d[ ,-c(10,11)]
>>>>>>>      d2<-d[complete.cases(d), ]
>>>>>>>      d2$V4<-as.numeric(d2$V4)
>>>>>>>      congruent <- (d2$V4 == 1) == TRUE
>>>>>>>      x <- get_tlbs(d2$V14, congruent, prior_weights = NULL, method = 
>>>>>>> "weighted", fill_gaps = FALSE)
>>>>>>>      write.table(x, paste0(i,".tlbs.txt"), quote=FALSE, row.names=TRUE)}
>>>>>>>
>>>>>>> I've also tried:
>>>>>>>
>>>>>>> for(i in txt.files){
>>>>>>>      d <- read.table(paste(i,sep=""),header=F)
>>>>>>>      if (0 %in% d)
>>>>>>>      {replace_with_na(d,replace = list(x = 0))} # replace zeros with NA
>>>>>>>      d<-d[ ,-c(10,11)]
>>>>>>>      d2<-d[complete.cases(d), ]
>>>>>>>      d2$V4<-as.numeric(d2$V4)
>>>>>>>      congruent <- (d2$V4 == 1) == TRUE
>>>>>>>      x <- get_tlbs(d2$V14, congruent, prior_weights = NULL, method = 
>>>>>>> "weighted", fill_gaps = FALSE)
>>>>>>>      write.table(x, paste0(i,".summaryoutput.txt"), quote=FALSE, 
>>>>>>> row.names=TRUE)}
>>>>>>>
>>>>>>> Thank you for your help.
>>>>>>> Sincerely
>>>>>>> Helen
>>>>>>>
>>>>>>>          [[alternative HTML version deleted]]
>>>>>>>
>>>>>>> ______________________________________________
>>>>>>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
>>>>>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>>>>>> PLEASE do read the posting guide 
>>>>>>> http://www.R-project.org/posting-guide.html
>>>>>>> and provide commented, minimal, self-contained, reproducible code.
>>>>>>>
>>>>>>
>>>>>>         [[alternative HTML version deleted]]
>>>>>>
>>>>>> ______________________________________________
>>>>>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
>>>>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>>>>> PLEASE do read the posting guide 
>>>>>> http://www.R-project.org/posting-guide.html
>>>>>> and provide commented, minimal, self-contained, reproducible code.
>>>>>>
>>>>>>
>>>>>
>>>>> --
>>>>> Michael
>>>>> http://www.dewey.myzen.co.uk/home.html
>>>>
>>>> ______________________________________________
>>>> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
>>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>>> PLEASE do read the posting guide 
>>>> http://www.R-project.org/posting-guide.html
>>>> and provide commented, minimal, self-contained, reproducible code.
>

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