Hi Peter,
I worked out a neat function to add the century to short dates. It
works fine on its own, but sadly it bombs when used with sapply. Maybe
someone else can point out my mistake:
add_century<-function(x,changeover=68,previous=19,current=20,pos=1,sep="-") {
xsplit<-unlist(strsplit(x,sep))
# only add century to short dates
if(nchar(xsplit[pos]) < 3) {
century<-ifelse(as.numeric(xsplit[pos]) <= changeover,current,previous)
xsplit[pos]<-paste0(century,xsplit[[pos]])
}
return(paste(xsplit,collapse=sep))
}
# these work
add_century(x3[1],changeover=1,pos=3,sep="/")
add_century(x3[2],changeover=1,pos=3,sep="/")
add_century(x3[3],changeover=1,pos=3,sep="/")
# this doesn't
sapply(x3,add_century,list(changeover=1,pos=3,sep="/"))
Jim
On Fri, Apr 17, 2020 at 11:30 AM Jim Lemon <drjimle...@gmail.com> wrote:
>
> Hi Peter,
> One way is to process the strings before converting them to dates:
>
> x2<-c("45-12-03","01-06-24","04-9-15","1901-03-04")
> add_century<-function(x,changeover=68,previous=19,current=20) {
> centuries<-sapply(sapply(x,strsplit,"-"),"[",1)
> shortyears<-which(!(nchar(centuries)>2))
> century<-rep("",length(x))
>
> century[shortyears]<-ifelse(centuries[shortyears]>changeover,previous,current)
> newx<-paste0(century,x)
> return(newx)
> }
> add_century(x2,1)
>
> Jim
>
> On Fri, Apr 17, 2020 at 12:34 AM Peter Nelson via R-help
> <r-help@r-project.org> wrote:
> >
> > I have a data set (.csv) with date (eg date of birth) information stored as
> > character vectors that I’m attempting to transform to POSIXct objects using
> > the package lubridate (1.7.4). The problem that I’m trying to address is
> > that my two digit years are invariably (?) parsed to 20xx. For example,
> >
> > x <- c("45-12-03","01-06-24","64-9-15”)
> > ymd(x)
> > [1] "2045-12-03" "2001-06-24" "2064-09-15”
> >
> > These should be parsed as “1945-12-03” “2001-06-24” “1964-09-15”.
> >
> > I've tried to use parse_date_time()—based on the documentation it looks to
> > me as though the argument cutoff_2000 should allow me to address this, but
> > it’s unclear to me how to implement this. As an example, I’ve tried
> >
> > parse_date_time(x, cutoff_2000 = 01)
> >
> > but get the following error message (and similar for other similar
> > attempts, including cutoff_2000 = 01L)
> >
> > Error in parse_date_time(x, cutoff_2000 = 1) :
> > unused argument (cutoff_2000 = 1)
> >
> > Thanks for your help!
> >
> > Peter Nelson, PhD
> > Institute of Marine Sciences
> > University of California, Santa Cruz
> > Center for Ocean Health, Long Marine Lab
> > 115 McAllistair Way
> > Santa Cruz, CA, 95076, USA
> > 707-267-5896
> >
> >
> >
> >
> >
> >
> > [[alternative HTML version deleted]]
> >
> > ______________________________________________
> > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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> > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
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