Hello everyone,
I have the following dataframe
library(dplyr)
dput(df)
structure(list(Freq = c(19L, 19L, 18L, 15L, 14L, 13L, 13L, 12L,
11L, 11L, 11L, 10L, 10L, 10L, 10L, 10L, 10L, 10L, 9L), word1 =
structure(c(3L,
11L, 5L, 6L, 11L, 3L, 7L, 10L, 8L, 11L, 13L, 1L, 1L, 4L, 5L,
9L, 12L, 14L, 2L), .Label = c("a", "art", "at", "by", "for",
"for ", "i", "is", "on", "said", "the", "there", "to", "when"
), class = "factor"), word2 = structure(c(13L, 12L, 13L, 13L,
6L, 13L, 5L, 8L, 11L, 4L, 2L, 3L, 10L, 13L, 13L, 13L, 1L, 9L,
7L), .Label = c("are", "be", "bit", "bottom", "dont", "end",
"hotel", "in", "it", "little", "one", "rest", "the"), class = "factor"),
word3 = structure(c(5L, 9L, 6L, 7L, 9L, 11L, 13L, 1L, 9L,
9L, 2L, 9L, 3L, 5L, 6L, 10L, 12L, 4L, 8L), .Label = c("a",
"able", "bit", "comes", "end", "first", "first ", "florence",
"of", "other", "same", "so", "want"), class = "factor"),
word4 = structure(c(5L, 9L, 10L, 8L, 9L, 10L, 11L, 7L, 9L,
9L, 11L, 1L, 5L, 5L, 6L, 2L, 4L, 11L, 3L), .Label = c("a",
"hand", "italy", "many", "of", "place", "statement", "states",
"the", "time", "to"), class = "factor")), class = "data.frame", row.names =
c(NA,
-19L))
Is there a way to modify the following command so that the filter function
doesn't return all the Levels?
filter(df,(word1 == 'for' & word2 == 'the' & word3 == 'first')) $ word4
[1] time place
Levels: a hand italy many of place statement states the time to
Thanks a lot!
Elahe
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
