Hello everyone, I have the following dataframe
library(dplyr) dput(df) structure(list(Freq = c(19L, 19L, 18L, 15L, 14L, 13L, 13L, 12L, 11L, 11L, 11L, 10L, 10L, 10L, 10L, 10L, 10L, 10L, 9L), word1 = structure(c(3L, 11L, 5L, 6L, 11L, 3L, 7L, 10L, 8L, 11L, 13L, 1L, 1L, 4L, 5L, 9L, 12L, 14L, 2L), .Label = c("a", "art", "at", "by", "for", "for ", "i", "is", "on", "said", "the", "there", "to", "when" ), class = "factor"), word2 = structure(c(13L, 12L, 13L, 13L, 6L, 13L, 5L, 8L, 11L, 4L, 2L, 3L, 10L, 13L, 13L, 13L, 1L, 9L, 7L), .Label = c("are", "be", "bit", "bottom", "dont", "end", "hotel", "in", "it", "little", "one", "rest", "the"), class = "factor"), word3 = structure(c(5L, 9L, 6L, 7L, 9L, 11L, 13L, 1L, 9L, 9L, 2L, 9L, 3L, 5L, 6L, 10L, 12L, 4L, 8L), .Label = c("a", "able", "bit", "comes", "end", "first", "first ", "florence", "of", "other", "same", "so", "want"), class = "factor"), word4 = structure(c(5L, 9L, 10L, 8L, 9L, 10L, 11L, 7L, 9L, 9L, 11L, 1L, 5L, 5L, 6L, 2L, 4L, 11L, 3L), .Label = c("a", "hand", "italy", "many", "of", "place", "statement", "states", "the", "time", "to"), class = "factor")), class = "data.frame", row.names = c(NA, -19L)) Is there a way to modify the following command so that the filter function doesn't return all the Levels? filter(df,(word1 == 'for' & word2 == 'the' & word3 == 'first')) $ word4 [1] time place Levels: a hand italy many of place statement states the time to Thanks a lot! Elahe ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.