?list.files and ?regexp
Warning: following obviously untested:
Gfiles <- list.files("G:", pattern = ".*10806\\.xls$")
should then give you a vector of character names of the files you want to
feed to read.xls() or whatever function exists in the favored package is
for reading Excel files these days.
Cheers,
Bert
On Thu, Dec 26, 2019 at 9:54 AM Thomas Subia <tsu...@imgprecision.com>
wrote:
> Colleagues,
>
> I have two locations where my data resides.
> One folder is for data taken under treatment A
> One folder is for data taken under treatment B
>
> "G:\ 0020-49785 10806.xls"
> "Q:\ 301864 4519 10806.xls"
>
> Here the 10806 is the part which is common to both directories.
>
> Is there a way to have R extract parts common to both directories?
>
> Thomas Subia
> Statistician / Senior Quality Engineer
> ASQ CQE
>
> IMG Companies
> 225 Mountain Vista Parkway
> Livermore, CA 94551
> T. (925) 273-1106
> F. (925) 273-1111
> E. tsu...@imgprecision.com
>
>
> Precision Manufacturing for Emerging Technologies
> imgprecision.com
>
> The contents of this message, together with any attachments, are intended
> only for the use of the individual or entity to which they are addressed
> and may contain information that is legally privileged, confidential and
> exempt from disclosure. If you are not the intended recipient, you are
> hereby notified that any dissemination, distribution, or copying of this
> message, or any attachment, is strictly prohibited. If you have received
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>
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