Greetings,
I have a data set look like this:
> print(MyResult)
2 5 9 10
11 13
mean 6.108394 3.272211e+01 3.951703e+02 2.086217e+03
79.838867 2.592272e+04
median 1.288889 2.743511e+00 4.061491e+00 4.943710e+01
-2.821667 -3.040625e+00
var 2885.350595 2.343144e+05 1.022680e+06 1.200589e+07
365179.508831 3.363738e+09
sd 53.715460 4.840603e+02 1.011276e+03 3.464952e+03
604.300843 5.799774e+04
valid.n 83501.000000 2.699000e+03 2.600000e+01 1.000000e+01
491.000000 5.000000e+00
14 17 19 20 21
mean 226.58561 273.2301 1611.224 620.8836 3608.207
median 51.68978 56.7179 1266.557 140.8548 459.320
var 758255.12696 485670.6679 2393157.095 1232059.4957 38426150.479
sd 870.77846 696.9008 1546.983 1109.9818 6198.883
valid.n 118.00000 90.0000 58.000 77.0000 15.000
attr(,"class")
[1] "dstat"
The above data set was generated from brkdn function and the numbers 2,
5, and etc. indicate the levels in my breakdown. Now, I want to have a
data frame looks like shown below so that I can save it into my
database:
Level mean median var sd valid.n
2 6.11 1.29 2885 53.72 8.35e+04
5 32.72 2.74 2.343e+05 484.1 2699
9 395.2 4.06 1.023e+06 1011 26
10 2086 49.44 1.201e+07 3465 10
11 79.84 -2.82 3.652e+05 604.3 491
13 2.592e+04 -3.04 3.364e+09 5.8e+04 5
14 226.6 51.69 7.583e+05 870.8 118
17 273.2 56.72 4.857e+05 696.9 90
19 1611 1267 2.393e+06 1547 58
20 620.9 140.8 1.232e+06 1110 77
21 3608 459.3 3.843e+07 6199 15
How can I do it?
Thanks in advance for your help,
Willa
This message contains confidential information and is in...{{dropped:8}}
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
