Would be nice to put those two way examples in the documentation of the
function 'expression' and 'bquote' in the next R version (we are in the
base) for other users ;-) I am sure many would enjoy.
Le 20/10/2019 à 19:15, Patrick Giraudoux a écrit :
> Great ! You have helped to solve a problem on which I was sweating
> (sporadically, however) since months...
>
> Thanks,
>
> Best,
>
>
> Le 20/10/2019 à 18:29, Bert Gunter a écrit :
>> The legend must be "an expression vector."
>> c("Sans renard",bquote(.(densren) (ind./km)^2)) is not because the
>> first element is a character string.
>>
>> This works:
>>
>> plot(1:100,1:100,type="n")
>> legend(list(x=0,y=100),legend=c(expression("Sans
>> renard"),bquote(.(densren)
>> (ind./km)^2)),lty=c(1,2),col=c("black","red"),bty="n")
>>
>> Cheers,
>> Bert
>>
>>
>> Bert Gunter
>>
>> "The trouble with having an open mind is that people keep coming
>> along and sticking things into it."
>> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>>
>>
>> On Sun, Oct 20, 2019 at 9:02 AM Patrick Giraudoux
>> <patrick.giraud...@univ-fcomte.fr
>> <mailto:patrick.giraud...@univ-fcomte.fr>> wrote:
>>
>> Thanks Bert and Peter,
>>
>> Yes Bert, I was aware of the legend() function syntax, and just
>> quoting the legend argument within the function.
>>
>> However, Bert and Peter, I do not understand why it works with
>> your absolutely reproducible examples and not in the slightly
>> (not so slightly apparently) different context where I used it...
>>
>> densren=1.25
>> plot(1:100,1:100,type="n")
>> legend(list(x=0,y=100),legend=c("Sans renard",bquote(.(densren)
>> (ind./km)^2)),lty=c(1,2),col=c("black","red"),bty="n")
>>
>> densren=1.25
>> plot(1:100,1:100,type="n")
>> legend(list(x=0,y=100),legend=c("Sans renard",bquote(.(densren) *
>> " ind."/"km"^2)),lty=c(1,2),col=c("black","red"),bty="n"
>>
>> Probably because the result of bquote() is concatenated in a
>> character vector, but how to deal with this ?
>>
>> Best,
>>
>> Patrick
>>
>>
>>
>> Le 20/10/2019 à 16:42, Bert Gunter a écrit :
>>> Assuming you are using base graphics, your syntax for adding the
>>> legend appears to be wrong.
>>> legend() is a separate function, not a parameter of plot.default
>>> afaics.
>>>
>>> The following works for me:
>>>
>>> > densren <- 1.25
>>> > plot(1:10)
>>> > legend (x="center", legend =bquote(.(densren) (ind./km)^2))
>>>
>>> See ?legend
>>>
>>> Bert Gunter
>>>
>>> "The trouble with having an open mind is that people keep coming
>>> along and sticking things into it."
>>> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>>>
>>>
>>> On Sun, Oct 20, 2019 at 5:30 AM Patrick Giraudoux
>>> <patrick.giraud...@univ-fcomte.fr
>>> <mailto:patrick.giraud...@univ-fcomte.fr>> wrote:
>>>
>>> Dear listers,
>>>
>>> I am trying to pass an expression inlcuding a variable and a
>>> superpscript to a legend. What I want to obtain is e.g. with
>>> densren = 1.25
>>>
>>> 1.25 ind./km^2
>>>
>>> I have tried many variants of the following:
>>>
>>> legend=bquote(.(densren) (ind./km)^2)
>>>
>>> but if not errors, do obtain
>>>
>>> 1.25 (ind./km^2)
>>>
>>> hence not what I want (no parenthesis, 2 in superscript...)
>>>
>>> Any idea about a correct syntax to get what I need ?
>>>
>>> Best,
>>>
>>> Patrick
>>>
>>>
>>> [[alternative HTML version deleted]]
>>>
>>> ______________________________________________
>>> R-help@r-project.org <mailto:R-help@r-project.org> mailing
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>>> PLEASE do read the posting guide
>>> http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible
>>> code.
>>>
>>
>
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